This post is written by Paramdeep.
Today, let us learn how to use NPV() function in Excel & create a simple financial model.
NPV – Introduction:
If you are dealing with cash and valuations, you are bound to have come across the NPV function. If you don’t know the assumptions behind the same, I bet it could cost you your job!
Let’s take a simple project – You buy a MSFT stock for USD 100. You receive a dividend of USD 10 in the first year, USD 20 in the second year, USD 40 in the third year and then you sell it out for USD 140. If you could have alternatively put this money in bank at 10% interest rate, have you gained anything?
How do you model this in excel? In this tutorial we understand how you can use NPV to do this analysis and what kind of pitfalls you can land into!!
What is the NPV() function
Simply speaking, NPV function calculates present value of your cash flows. Let’s take a simple example first –
You invest $100 in a bank, which pays 10% interest
- What is its value 1 year down the line?
- I am sure, you don’t need any coffee to get that value – 100 x 10% is the interest and 100 is the principal that you had. So the value 100 x (1+10%) = 110
- What about 2 years?
- Simple 100 x (1 + 10%)^2 = 121
- So, if I were to ask you, the present value of a cash flow of 121, that you were to get 2 years down the line at 10% interest?
- Again simple, you told me initially, it was $100
NPV does exactly that – gets you the present value of your cash flows
The function is simple, it does all the difficult calculations for you and gets you the solution!
Beware – The function has its own assumptions!
Though the function is quite convenient, but it has its own pitfalls. And in my modelling experience I have seen a lot of people making that mistake! Lets model the situation described in the beginning (The MSFT Case). The cash flows are given to you as:
Let us see, internally what we get by modelling the NPV from the first principles and using the NPV function
You can clearly see that there are two ways of using NPV function (and each has its own assumption!)
So what is happening internally?
Usually when we start a project, we assume that the investment is made upfront (On day 0). Then the revenues, costs and the cash would start flowing in. Since the investment is made on day 0, it should not be discounted.
But when you use the NPV function, excel internally makes an assumption that even the first cash flow is at the end of the year (Per se, this is not wrong, but in normal circumstances, you make the payment upfront!).
So the right usage of the function would be to add the first cash without discounting and then use the NPV function to discount the rest of the cash flows.
If you just use the NPV function on all the cash flows, then the inherent assumption is that even the first cash flow is at the end of the year.
Few other ways of calculating NPV
When you are dealing with cash flows and valuations (typically that is when you come across the functions like NPV, etc) even small mistakes cost dear. You want to make sure that you are as accurate as you can ever be. At that point of time, if the cash is not flowing at the year ends, you can use a more powerful function in excel – XNPV. You can show it the cash and the exact dates and it would calculate the exact NPV for you. People don’t often use it as they don’t know the exact dates of cash flow!
How do you calculate the discounted cash values in your models?
I know the easiest way would be to use the NPV function. It is easy to use but at the same time could be tricky. So how do you implement such functionality in your models?
Templates to download
I have created a template for you, where the subheadings are given and you have use the functions to get the right values for you! You can download the same from here. You can go through the case and fill in the yellow boxes. I also recommend that you try to create this structure on your own (so that you get a hang of what information is to be recorded).
Also you can download this filled template and check, if the information you recorded, matches mine or not!
For any queries regarding the cash impact or financial modeling, feel free to put the comments in the blog or write an email to paramdeep@edupristine.com
Join our Financial Modeling Classes
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Learn more about Financial Modeling:
Go thru these articles to learn more about Excel Financial Modeling:
- Excel Financial Modeling – 6 part tutorial
- Introduction to Project Finance
- Using MOD() function to implement frequency escalation in Excel
- Creating a P&L Reporting Model in Excel – 6 part tutorial
The article is written by Paramdeep from Pristine.
Chandoo.org has partnered with Pristine to launch a Financial Modeling Course. For details click here.
20 Responses to “Simulating Dice throws – the correct way to do it in excel”
You have an interesting point, but the bell curve theory is nonsense. Certainly it is not what you would want, even if it were true.
Alpha Bravo - Although not a distribution curve in the strict sense, is does reflect the actual results of throwing two physical dice.
And reflects the following . .
There is 1 way of throwing a total of 2
There are 2 ways of throwing a total of 3
There are 3 ways of throwing a total of 4
There are 4 ways of throwing a total of 5
There are 5 ways of throwing a total of 6
There are 6 ways of throwing a total of 7
There are 5 ways of throwing a total of 8
There are 4 ways of throwing a total of 9
There are 3 ways of throwing a total of 10
There are 2 ways of throwing a total of 11
There is 1 way of throwing a total of 12
@alpha bravo ... welcome... 🙂
either your comment or your dice is loaded 😉
I am afraid the distribution shown in the right graph is what you get when you throw a pair of dice in real world. As Karl already explained, it is not random behavior you see when you try to combine 2 random events (individual dice throws), but more of order due to how things work.
@Karl, thanks 🙂
When simulating a coin toss, the ROUND function you used is appropriate. However, your die simulation formula should use INT instead of ROUND:
=INT(RAND()*6)+1
Otherwise, the rounding causes half of each number's predictions to be applied to the next higher number. Also, you'd get a count for 7, which isn't possible in a die.
To illustrate, I set up 1200 trials of each formula in a worksheet and counted the results. The image here shows the table and a histogram of results:
http://peltiertech.com/WordPress/wp-content/img200808/RandonDieTrials.png
@Jon: thanks for pointing this out. You are absolutely right. INT() is what I should I have used instead of ROUND() as it reduces the possibility of having either 1 or 6 by almost half that of having other numbers.
this is such a good thing to learn, helps me a lot in my future simulations.
Btw, the actual graphs I have shown were plotted based on randbetween() and not from rand()*6, so they still hold good.
Updating the post to include your comments as it helps everyone to know this.
By the way, the distribution is not a Gaussian distribution, as Karl points out. However, when you add the simulations of many dice together (i.e., ten throws), the overall results will approximate a Gaussian distribution. If my feeble memory serves me, this is the Central Limit Theorem.
@Jon, that is right, you have to nearly throw infinite number of dice and add their face counts to get a perfect bell curve or Gaussian distribution, but as the central limit theorem suggests, our curve should roughly look like a bell curve... 🙂
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I'm afraid to say that this is a badly stated and ambiguous post, which is likely to cause errors and misunderstanding.
Aside from the initial use of round() instead of int(),.. (you've since corrected), you made several crucial mistakes by not accurately and unambiguously stating the details.
Firstly, you said:
"this little function generates a random fraction between 0 and 1"
Correctly stated this should be:
"this little function generates a random fraction F where 0 <= F < 1".
Secondly, I guess because you were a little fuzzy about the exact range of values returned by rand(), you have then been just as ambiguous in stating:
"I usually write int(rand()*12)+1 if I need a random number between 0 to 12".
(that implies 13 integers, not 12)
Your formula, does not return 13 integers between 0 to 12.
It returns 12 integers between 1 and 12 (inclusive).
-- As rand() returns a random fraction F where 0 <= F < 1, you can obviously can only get integers between 1 and 12 (inclusive) from your formula as stated above, but clearly not zero.
If you had said either:
"I usually write int(rand()*12) if I need a random number between 0 to 11 (inclusive)",
or:
"I usually write int(rand()*12)+1 if I need a random number between 1 to 12 (inclusive)"
then you would have been correct.
Unfortunately, you FAIL! -- repeat 5th grade please!
Your Fifth Grade Maths Teacher
Idk if I'm on the right forum for this or how soon one can reply, but I'm working on a test using Excel and I have a table set up to get all my answers from BUT I need to generate 10,000 answers from this one table. Every time, I try to do this I get 10,000 duplicate answers. I know there has to be some simple command I have left out or not used at all, any help would be extremely helpful! (And I already have the dice figured out lol)
Roll 4Dice with 20Sides (4D20) if the total < 20 add the sum of a rerolled 2D20. What is the average total over 10,000 turns? (Short and sweet)
Like I said when I try to simulate 10,000turns I just get "67" 10,000times -_- help please! 😀
@Justin
This is a good example to use for basic simulation
have a look at the file I have posted at:
https://rapidshare.com/files/1257689536/4_Dice.xlsx
It uses a variable size dice which you set
Has 4 Dice
Throws them 10,000 times
If Total per roll < 20 uses the sum of 2 extra dice Adds up the scores Averages the results You can read more about how it was constructed by reading this post: http://chandoo.org/wp/2010/05/06/data-tables-monte-carlo-simulations-in-excel-a-comprehensive-guide/
Oh derp, i fell for this trap too, thinking i was makeing a good dice roll simulation.. instead of just got an average of everything 😛
Noteably This dice trow simulate page is kinda important, as most roleplay dice games were hard.. i mean, a crit failure or crit hit (rolling double 1's or double 6's) in a a game for example dungeons and dragons, if you dont do the roll each induvidual dice, then theres a higher chance of scoreing a crit hit or a crit failure on attacking..
I've been working on this for awhile. So here's a few issues I've come across and solved.
#1. round() does work, but you add 0.5 as the constant, not 1.
trunc() and int() give you the same distributions as round() when you use the constant 1, so among the three functions they are all equally fair as long as you remember what you're doing when you use one rather than the other. I've proven it with a rough mathematical proof -- I say rough only because I'm not a proper mathematician.
In short, depending on the function (s is the number of sides, and R stands in for RAND() ):
round(f), where f = sR + 0.5
trunc(f), where f = sR + 1
int(f), where f = sR + 1
will all give you the same distribution, meaning that between the three functions they are fair and none favors something more than the others. However...
#2. None of the above gets you around the uneven distribution of possible outcomes of primes not found in the factorization of the base being used (base-10, since we're using decimal; and the prime factorization of 10 is 2 and 5).
With a 10-sided die, where your equation would be
=ROUND(6*RAND()+0.5)
Your distribution of possible values is even across all ten possibilities.
However, if you use the most basic die, a 6-sided die, the distributions favor some rolls over others. Let's assume your random number can only generate down to the thousandths (0.000 ? R ? 0.999). The distribution of possible outcomes of your function are:
1: 167
2: 167
3: 166
4: 167
5: 167
6: 166
So 4 and 6 are always under-represented in the distribution by 1 less than their compatriots. This is true no matter how many decimals you allow, though the distribution gets closer and closer to equal the further towards infinite decimal places you go.
This carries over to all die whose numbers of sides do not factor down to a prime factorization of some exponential values of 2 and 5.
So, then, how can we fix this one, tiny issue in a practical manner that doesn't make our heads hurt or put unnecessary strain on the computer?
Real quick addendum to the above:
Obviously when I put the equation after the example of the 10-sided die, I meant to put a 10*RAND() instead of a 6*RAND(). Oops!
Also, where I have 0.000 ? R ? 0.999, the ?'s are supposed to be less-than-or-equal-to signs but the comments didn't like that. Oh well.
How do you keep adding up the total? I would like to have a cell which keeps adding up the total sum of the two dices, even after a new number is generated in the cells when you refresh or generate new numbers.
So, how do you simulate rolling 12 dice? Do you write int(rand()*6) 12 times?
Is there a simpler way of simulating n dice in Excel?
I've run this code in VBA
Sub generate()
Application.ScreenUpdating = False
Application.Calculation = False
Dim app, i As Long
Set app = Application.WorksheetFunction
For i = 3 To 10002
Cells(i, 3).Value = i - 2
Cells(i, 4).Value = app.RandBetween(2, 12)
Cells(i, 5).Value = app.RandBetween(1, 6) + app.RandBetween(1, 6)
Next
Application.ScreenUpdating = True
Application.Calculation = True
End Sub
But I get the same distribution for both columns 4 and 5
Why ?
@Mohammed
I would expect to get the same distribution as you have effectively used the same function