Today we will learn an interesting animation technique that ONLY uses, … wait for it …, Excel Formulas. That is right, we will use simple formulas to animate values in Excel.
Intrigued? Confused? Interested?
First see these Excel animation demos:
Animated icons & fill-color
Animated In-cell Charts
Click here to download the workbook with these examples.
What is the secret sauce behind this animation?
Take 1 portion of crushed basil leaves, 2 portions of grounded roasted coffee beans and mix them with hot water. Add enough sugar and throw it away. 😛
Now, come back to your excel workbook and use circular references to generate the animation effect.
Understanding how Circular References & Iterative Calculation Mode work
In order to get this animation, you should be familiar with two excel magic spells – Circular References & Iterative Calculations. In simple terms,
Circular Reference: is when a cell refers to itself in the formula. For eg. in cell A1, if you write =A1+1, it is a circular reference. The reference can be both direct or in-direct (ie you can refer to cell B1, which refers to A1 again).
Iterative Calculation: If a cell has circular reference, excel can quickly go in to infinite loop (not the place where Apple is head-quartered). To avoid this, we use iterative calculation mode. When you enable this mode, excel solves the cell references only a certain number of times.
Here is an excellent guide on circular references.
How to enable iterative calculation mode?
Simple, go to Excel options > Formulas and then select iterative mode. Change the number of iterations to a large value (so that we can see some animation). Like this:
How to use Circular References & Iterative Mode for Animation?
It doesn’t take a lot of coffee to conclude that using circular references & iterative mode of calculation, we can increment a cell value from 1 to 100 (or 4000, if you fancy).
Assuming you want to increment the value in A1 from 0 to 100, and A2 is used to control the animation (ie if you type “Yes” in a2, only then we increment the values).
In cell A1, we write =IF(A2=”yes”,IF(A1>=100,A1,A1+1),0)
If iterative mode is enabled, when you enter yes in cell A2, you can see the value in A1 going from 0 to 100, very fast.
Now, if you change the formula to =IF(A2=”yes”,IF(A1>=4000,A1,A1+1),0), you can see the cell value in A1 going up from 0 to 4,000 in a few seconds.
But, what about animation?!?
Now that we have the cell A1 changing its value when we want, we just need to link this with conditional formatting to get some magic.
For eg. you can apply conditional formatting on A1 with the following rule to change cell color as the value increases.
Similarly, you can use the value in A1 to draw in-cell charts that grow as the value changes in A1.
Just let your imagination run wild.
Where can you use such animation?
Animation is a powerful attention grabber. I think you can use this type of animation in dashboards to display alerts. For eg. you can highlight portions of dashboard that changed when a different product (or month) is selected.
That said, I strongly recommend against overuse of animation effects. They can quickly become annoying. Not to mention, they are cumbersome to maintain (and add little value).
What are the limitations of Circular Reference based animation?
- You must enable iterative mode of calculation.
- This doesn’t work with charts. Excel charts do not pick up cell values unless the calculation is finished. So you cannot plug values in to charts to expect animated charts. If you are curious to build one, see Daniel’s animated business charts example.
- This can slowdown your workbook: Whenever you run the animation, excel is going to do thousands of calculations and this will slowdown your workbook.
Download Excel Animation Workbook
I have put together a simple workbook showcasing several examples of this technique. Download and play with it.
Excel 2007 link | Excel 2003 link
(Make sure you have turned on the iterative mode.)
Do you find this technique interesting?
To be frank, I find this technique more amusing than useful. But I wrote about it anyway as it shows what is possible with excel. It can be useful in situations where there is too much information and you need to call users attention to something.
What about you? Do you see any practical applications for this technique? Share your ideas and opinions thru comments.
14 Responses to “How many ‘Friday the 13th’s are in this year? [Formula fun + challenge]”
in C3=2016
in C4=3
in C5=1 (the first next year with three Friday the 13ths)
=SMALL(IF(MMULT(--(MOD(DATE(C3+ROW(1:1000),COLUMN(A:L),13),7)=6),ROW(1:12)^0)=C4,C3+ROW(1:1000)),C5)
formula check in the next 1000 years
This will generate a table of counts of Friday the 13th's by year. If I didn't screw it up the next year with three is 2026.
I created a simple parameter table with a start date and end date that I wanted to evaluate. That calculates the number of days and generates a list of those days. Then filter and group. The generation of the list in power query (i.e. without populating a date table in excel) is pretty cool, otherwise this isn't really doing anything than creating a big date and filtering/counting.
let
Source = List.Dates(StartDateAsDate, Days2, #duration(1,0,0,0)),
ConvertDateListToTable = Table.FromList(Source, Splitter.SplitByNothing(), null, null, ExtraValues.Error),
AddDayOfMonthColumn = Table.AddColumn(ConvertDateListToTable, "DayOfMonth", each Date.Day([Column1])),
AddYearColumn = Table.AddColumn(AddDayOfMonthColumn, "Year", each Date.Year([Column1])),
AddDayOfWeekColumn = Table.AddColumn(AddYearColumn, "Day of Week", each Date.DayOfWeek([Column1])),
FilterFriday13 = Table.SelectRows(AddDayOfWeekColumn, each ([DayOfMonth] = 13) and ([Day of Week] = 5)),
Friday13thsByYear = Table.Group(FilterFriday13, {"Year"}, {{"Number of Friday the 13ths!", each Table.RowCount(_), type number}})
in
Friday13thsByYear
With the parameters replaced by values should you want to play along at home. This runs for 20 years starting on 1/1/2016.
let
Source = List.Dates(#date(2016,1,1), 7300, #duration(1,0,0,0)),
ConvertDateListToTable = Table.FromList(Source, Splitter.SplitByNothing(), null, null, ExtraValues.Error),
AddDayOfMonthColumn = Table.AddColumn(ConvertDateListToTable, "DayOfMonth", each Date.Day([Column1])),
AddYearColumn = Table.AddColumn(AddDayOfMonthColumn, "Year", each Date.Year([Column1])),
AddDayOfWeekColumn = Table.AddColumn(AddYearColumn, "Day of Week", each Date.DayOfWeek([Column1])),
FilterFriday13 = Table.SelectRows(AddDayOfWeekColumn, each ([DayOfMonth] = 13) and ([Day of Week] = 5)),
Friday13thsByYear = Table.Group(FilterFriday13, {"Year"}, {{"Number of Friday the 13ths!", each Table.RowCount(_), type number}})
in
Friday13thsByYear
=MATCH(3,MMULT(N(WEEKDAY(DATE(C3+ROW(1:100)-1,COLUMN(A:L),13))=6),1^ROW(1:12)),)+C3-1
It should be pointed out that Alex's solution, unlike some others, has the additional advantage of being non-array. My solution was nearly identical but with -- and SIGN instead of N and 1^.
=C3-1+MATCH(3,MMULT(--(WEEKDAY(DATE(C3-1+ROW(1:25),COLUMN(A:L),13))=6),SIGN(ROW(1:12))),0)
Sub Friday13()
Dim StartDate As Date
Dim EndDate As Date
Dim x As Long
Dim r As Long
Range("C7:C12").ClearContents
StartDate = CDate("01/01/" & Range("C3"))
EndDate = CDate("31/12/" & Range("C3"))
r = 7
For x = StartDate To EndDate
If Day(x) = 13 And Weekday(x, vbMonday) = 5 Then
Cells(r, 3) = Month(x)
r = r + 1
End If
Next
End Sub
Calculate next year with 3 Friday 13th. Good for 100 years different from year entered in cell C3
Sub ThreeFriday13()
Dim StartDate As Date
Dim EndDate As Date
Dim x As Long
Dim WhatYear As Integer
Dim Counter As Integer
Range("E7").ClearContents
StartDate = CDate("01/01/" & Range("C3") + 1)
EndDate = CDate("31/12/" & Range("C3") + 100)
Counter = 0
For x = StartDate To EndDate
If WhatYear Year(x) Then
WhatYear = Year(x)
'Different year so reset counter
Counter = 0
End If
If Day(x) = 13 And Weekday(x, vbMonday) = 5 Then
Counter = Counter + 1
If Counter = 3 Then
WhatYear = Year(x)
Exit For
End If
End If
Next
Range("E7") = WhatYear
End Sub
*RE-POST as not equal did not show earliuer
Calculate next year with 3 Friday 13th. Good for 100 years different from year entered in cell C3
Sub ThreeFriday13()
Dim StartDate As Date
Dim EndDate As Date
Dim x As Long
Dim WhatYear As Integer
Dim Counter As Integer
Range("E7").ClearContents
StartDate = CDate("01/01/" & Range("C3") + 1)
EndDate = CDate("31/12/" & Range("C3") + 100)
Counter = 0
For x = StartDate To EndDate
If WhatYear NE Year(x) Then
WhatYear = Year(x)
'Different year so reset counter
Counter = 0
End If
If Day(x) = 13 And Weekday(x, vbMonday) = 5 Then
Counter = Counter + 1
If Counter = 3 Then
WhatYear = Year(x)
Exit For
End If
End If
Next
Range("E7") = WhatYear
End Sub
earlier*
I've a doubt with using array formula here.
In sample workbook, I tried to replicate the formula again.
=IFERROR(SMALL(IF(WEEKDAY(DATE($C$3,ROW($A$1:$A$12),13))=6,ROW($A$1:$A$12)),$B7),"")
For this I selected C7 to C12, and typed the same formula and pressed ctrl+alt+Enter. But in all cells it is taking $B7 (and not $B7, $B8, $B9.... etc)
and since it is array formula I can't edit individual cell.
Please guide.
Thanks
Hi Chandoo,
Cool stuff. You need to clarify that the answer of 5 represents the 1st month in the year that has a Friday the 13th, and not the number of Fridays the 13th in the year. Subtle, but important difference.
Thanks,
Pablo
I like the MMULT() function far more, but here's how I would have tackled it. It uses an EDATE() base and MODE() over 100 years. I'm assuming that 100 years is enough time to catch the next year with 3 friday 13th's. Array entered, of course.
{=MODE(IFERROR(YEAR(IF((WEEKDAY(EDATE(DATE(C3, 1, 13), ROW(INDIRECT("1:1200"))))=6), EDATE(DATE(C3, 1, 13), ROW(INDIRECT("1:1200"))), "")), ""))}
Finding all the Friday the 13ths in a Year:
=SUMPRODUCT((DAY(ROW(INDIRECT(DATE(C3,1,1)&":"&DATE(C3,12,31))))=13)*(TEXT(ROW(INDIRECT(DATE(C3,1,1)&":"&DATE(C3,12,31))),"ddd")="Fri"))
{=sum(if(day.of.week(DATe($YEAR;{1;2;3;4;5;6;7;8;9;10;11;12};13);1)=6;1;0))}
just list the years