Ensure cleaner input dates with conditional formatting [quick tip]

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Here is a familiar problem:

You create a workbook to track some data. You ask your staff to fill up the data. Almost all the input data is fine, except the date column. Every one types dates in their own format.

Here is a fun, simple & powerful way to warn your users when they enter wrong dates.

Use conditional formatting

Here is a quick demo:

cleaner-dates-with-excel-conditional-formatting-demo

cleaner-dates-with-conditional-formatting-setting up the rulesHow to ensure cleaner dates with conditional formatting?

  1. Let’s say your users need to enter date input in cell C3.
  2. Select C3 and go to Home > Conditional Formatting > New Rule
  3. Select the rule type as “Use a formula…”
  4. Use a formula like this: =ISERROR(DAY($C$3))
  5. Set up formatting to highlight incorrect dates
  6. Done

Explanation for the formula:

We will assume that C3 contains a valid date and try to do some sort of date operation on it, like finding the day of month using DAY($C$3). If this returns an error, that means we have an invalid date.

So to check the error status, we use ISERROR().

A caveat: dates are numbers

Since Excel dates are numbers, technically, your users can type a number in C3 (like 7) and our conditional formatting won’t trigger the error.

Bonus tip: Adding conditional formatting to an entire column

To add conditional formatting to an entire column,

  1. Let’s say the date inputs go to column C, starting with C3 as first input
  2. Select all the cells in column C that will have dates
  3. Set up the conditional formatting with below rule:
  4. =ISERROR(DAY($C3))

Download example workbook

Click here to download a simple example workbook with this technique. Examine the conditional formatting in C3 & D3 to learn more.

Do you use CF to nudge your users in right direction?

Excel Conditional Formatting is one of my all time favourite features. I use liberal amounts of CF on all my Excel recipes. I think CF makes a great ingredient if you are collecting user inputs.

What about you? Do you use conditional formatting to make sure your inputs are clean? What techniques do you use? Please share your thoughts and tips in the comments area.

Here are few more awesome ways to use conditional formatting:

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14 Responses to “How many ‘Friday the 13th’s are in this year? [Formula fun + challenge]”

  1. in C3=2016
    in C4=3
    in C5=1 (the first next year with three Friday the 13ths)

    =SMALL(IF(MMULT(--(MOD(DATE(C3+ROW(1:1000),COLUMN(A:L),13),7)=6),ROW(1:12)^0)=C4,C3+ROW(1:1000)),C5)

    formula check in the next 1000 years

  2. Brian says:

    This will generate a table of counts of Friday the 13th's by year. If I didn't screw it up the next year with three is 2026.

    I created a simple parameter table with a start date and end date that I wanted to evaluate. That calculates the number of days and generates a list of those days. Then filter and group. The generation of the list in power query (i.e. without populating a date table in excel) is pretty cool, otherwise this isn't really doing anything than creating a big date and filtering/counting.

    let
    Source = List.Dates(StartDateAsDate, Days2, #duration(1,0,0,0)),
    ConvertDateListToTable = Table.FromList(Source, Splitter.SplitByNothing(), null, null, ExtraValues.Error),
    AddDayOfMonthColumn = Table.AddColumn(ConvertDateListToTable, "DayOfMonth", each Date.Day([Column1])),
    AddYearColumn = Table.AddColumn(AddDayOfMonthColumn, "Year", each Date.Year([Column1])),
    AddDayOfWeekColumn = Table.AddColumn(AddYearColumn, "Day of Week", each Date.DayOfWeek([Column1])),
    FilterFriday13 = Table.SelectRows(AddDayOfWeekColumn, each ([DayOfMonth] = 13) and ([Day of Week] = 5)),
    Friday13thsByYear = Table.Group(FilterFriday13, {"Year"}, {{"Number of Friday the 13ths!", each Table.RowCount(_), type number}})
    in
    Friday13thsByYear

    • Brian says:

      With the parameters replaced by values should you want to play along at home. This runs for 20 years starting on 1/1/2016.

      let
      Source = List.Dates(#date(2016,1,1), 7300, #duration(1,0,0,0)),
      ConvertDateListToTable = Table.FromList(Source, Splitter.SplitByNothing(), null, null, ExtraValues.Error),
      AddDayOfMonthColumn = Table.AddColumn(ConvertDateListToTable, "DayOfMonth", each Date.Day([Column1])),
      AddYearColumn = Table.AddColumn(AddDayOfMonthColumn, "Year", each Date.Year([Column1])),
      AddDayOfWeekColumn = Table.AddColumn(AddYearColumn, "Day of Week", each Date.DayOfWeek([Column1])),
      FilterFriday13 = Table.SelectRows(AddDayOfWeekColumn, each ([DayOfMonth] = 13) and ([Day of Week] = 5)),
      Friday13thsByYear = Table.Group(FilterFriday13, {"Year"}, {{"Number of Friday the 13ths!", each Table.RowCount(_), type number}})
      in
      Friday13thsByYear

  3. Alex Groberman says:

    =MATCH(3,MMULT(N(WEEKDAY(DATE(C3+ROW(1:100)-1,COLUMN(A:L),13))=6),1^ROW(1:12)),)+C3-1

    • David N says:

      It should be pointed out that Alex's solution, unlike some others, has the additional advantage of being non-array. My solution was nearly identical but with -- and SIGN instead of N and 1^.

      =C3-1+MATCH(3,MMULT(--(WEEKDAY(DATE(C3-1+ROW(1:25),COLUMN(A:L),13))=6),SIGN(ROW(1:12))),0)

  4. SunnyKow says:

    Sub Friday13()

    Dim StartDate As Date
    Dim EndDate As Date
    Dim x As Long
    Dim r As Long

    Range("C7:C12").ClearContents
    StartDate = CDate("01/01/" & Range("C3"))
    EndDate = CDate("31/12/" & Range("C3"))
    r = 7
    For x = StartDate To EndDate
    If Day(x) = 13 And Weekday(x, vbMonday) = 5 Then
    Cells(r, 3) = Month(x)
    r = r + 1
    End If
    Next
    End Sub

    • SunnyKow says:

      Calculate next year with 3 Friday 13th. Good for 100 years different from year entered in cell C3

      Sub ThreeFriday13()

      Dim StartDate As Date
      Dim EndDate As Date
      Dim x As Long
      Dim WhatYear As Integer
      Dim Counter As Integer

      Range("E7").ClearContents
      StartDate = CDate("01/01/" & Range("C3") + 1)
      EndDate = CDate("31/12/" & Range("C3") + 100)
      Counter = 0

      For x = StartDate To EndDate
      If WhatYear Year(x) Then
      WhatYear = Year(x)
      'Different year so reset counter
      Counter = 0
      End If
      If Day(x) = 13 And Weekday(x, vbMonday) = 5 Then
      Counter = Counter + 1
      If Counter = 3 Then
      WhatYear = Year(x)
      Exit For
      End If
      End If
      Next
      Range("E7") = WhatYear

      End Sub

      • SunnyKow says:

        *RE-POST as not equal did not show earliuer
        Calculate next year with 3 Friday 13th. Good for 100 years different from year entered in cell C3

        Sub ThreeFriday13()

        Dim StartDate As Date
        Dim EndDate As Date
        Dim x As Long
        Dim WhatYear As Integer
        Dim Counter As Integer

        Range("E7").ClearContents
        StartDate = CDate("01/01/" & Range("C3") + 1)
        EndDate = CDate("31/12/" & Range("C3") + 100)
        Counter = 0

        For x = StartDate To EndDate
        If WhatYear NE Year(x) Then
        WhatYear = Year(x)
        'Different year so reset counter
        Counter = 0
        End If
        If Day(x) = 13 And Weekday(x, vbMonday) = 5 Then
        Counter = Counter + 1
        If Counter = 3 Then
        WhatYear = Year(x)
        Exit For
        End If
        End If
        Next
        Range("E7") = WhatYear

        End Sub

  5. Devesh says:

    I've a doubt with using array formula here.
    In sample workbook, I tried to replicate the formula again.
    =IFERROR(SMALL(IF(WEEKDAY(DATE($C$3,ROW($A$1:$A$12),13))=6,ROW($A$1:$A$12)),$B7),"")
    For this I selected C7 to C12, and typed the same formula and pressed ctrl+alt+Enter. But in all cells it is taking $B7 (and not $B7, $B8, $B9.... etc)
    and since it is array formula I can't edit individual cell.
    Please guide.
    Thanks

  6. Pablo says:

    Hi Chandoo,
    Cool stuff. You need to clarify that the answer of 5 represents the 1st month in the year that has a Friday the 13th, and not the number of Fridays the 13th in the year. Subtle, but important difference.
    Thanks,
    Pablo

  7. Micah Dail says:

    I like the MMULT() function far more, but here's how I would have tackled it. It uses an EDATE() base and MODE() over 100 years. I'm assuming that 100 years is enough time to catch the next year with 3 friday 13th's. Array entered, of course.

    {=MODE(IFERROR(YEAR(IF((WEEKDAY(EDATE(DATE(C3, 1, 13), ROW(INDIRECT("1:1200"))))=6), EDATE(DATE(C3, 1, 13), ROW(INDIRECT("1:1200"))), "")), ""))}

  8. Jason Morin says:

    Finding all the Friday the 13ths in a Year:

    =SUMPRODUCT((DAY(ROW(INDIRECT(DATE(C3,1,1)&":"&DATE(C3,12,31))))=13)*(TEXT(ROW(INDIRECT(DATE(C3,1,1)&":"&DATE(C3,12,31))),"ddd")="Fri"))

  9. jmdias says:

    {=sum(if(day.of.week(DATe($YEAR;{1;2;3;4;5;6;7;8;9;10;11;12};13);1)=6;1;0))}
    just list the years

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