Free Picture Calendar Template – Download and make a personalized calendar today!

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Here is something fun, personalized and delicious to start your new year. A Picture Calendar built in Excel!

Printable 12 Month Picture Calendar

Using this you can print a 12 month calendar with your own photos. Its fun to use, easy to set up and looks great. See this demo to understand how it works.

Picture Calendar Template Demo

Download Picture Calendar Template

Click here to download the picture calendar template. Enable macros to use it. [6mb]

How to use this?

This is a very simple Excel template. Just follow these instructions.

  1. Once you download the file, you would find 4 sheets inside.
  2. Go to the Monthly Calendar tab and play with the calendar. If you want to change colors, fonts etc. do that.
  3. Now, go to Pics tab. Here we have 12 pics (preloaded with some cute cats & dogs)
  4. Remove all the pics and add your own.
  5. Once you added the pics, resize them so that they can fit in Column B (800 px). Each photo should take up 2 rows (total 600 px maximum)
  6. Once you have added the photos, arrange each photo in 1 cells, starting from B2 (thus 12th pic will be in B24&B25)
  7. That is all, go back to Monthly calendar to check out your own personalized picture calendar.

Bonus: Click on the “Make 12 month PDF” to generate 12 month-wise calendars pdfs.

How does this work?

This calendar uses some of my favorite techniques,

To help you understand how this works, I have made a short video explaining the template, the VBA code & formulas. Go ahead and watch it below:
(Watch it on our Youtube Channel)

Do you like this template?

How do you like this template? Are you planning to use this? Please share your comments, ideas with us. Go ahead and comment.

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19 Responses to “How to Distribute Players Between Teams – Evenly”

  1. Roshan Thayyil says:

    An excellent solution, especially for large data sets.

    Another solution without using solver would be to assign the player with the highest score to Team 1, the 2nd to team 2, 3rd to team 3, 4th to team 3, 5th to team 2, 6th to team 1, 7th to team 1 and it continues. This method would end up with a Std Dev of 0.001247219. This works best with a distribution with lower Std Dev for the dataset.

    Full Disclosure: this is not my idea, remember reading something a few years ago. Think it may have been Ozgrid

    • Roshan Thayyil says:

      thinking back I now remember why I read about it. About 10 years back I had to distribute around 300 team members into 25-30 odd teams. Used this method based on their performance scores. I used the method I described to do this and the distribution was pretty fair.

      Solver would have saved me a ton of time though 🙂

  2. I think the issue with you first Solver approach was that you took the absolute value of the sum of team deviations (which should always be zero except for rounding) instead of the sum of the absolute values (which is a reasonable measure of how unbalanced the teams are).

  3. Here's another simple algorithm you could use: you start from the top (with players sorted from high to low), and at each step allocate the next player to whichever team has the smallest total so far. You can implement it dynamically with some formulas so it will update automatically when the data changes.

    If the scores were more widely distributed (so that this might end up with not all teams the same size), you could add a constraint to only pick among the teams which currently have fewest players at each step, or just stop adding to any team when it hits its quota.

    When I tried it on the sample, I got the three teams below, with a STDEV of 0.000942809 (i.e. about half of what Solver got to).

    Team 1: John, Hugo, Tom, Josh, Eric, Zane, Charles, Andrew
    Team 2: Barry, Michael, Kenny, Joe, Xavier, Patrick, Oliver, William
    Team 3: Henry, Steven, Ben, Frank, Kyle, Edward, Cameron, Lachlan

    Thanks for sharing!

    • Ishaan says:

      Hi,
      I was looking at all the solutions and this is closest to what I intended to do. I am dividing a bunch of players into 3 soccer teams. Players availability is also a factor while deciding the teams.
      So the steps the excel needs to do is as follows:
      1) In availability column if "yes" go to next
      2) Equally divide 'Goalkeepers', 'Strikers', 'Defenders' basis their quality
      So the end result gives each 3 teams a balance of players playing at different positions.
      Can this be done on Google spreadsheet with only availability as an input from the user and rest calculates by itself.
      Sorry for asking such a pointed question, but I have been struggling to find a solution for it for sometime now!

      • Robin says:

        Hi Ishaan,

        I am working on a similar problem at the moment, so I am wondering if you ever found a solution and if you are willing to share what you did.

  4. Konrad says:

    Hi everyone, this is a variation of the famous Knapsack Problem https://en.wikipedia.org/wiki/Knapsack_problem.

    I had to use a VBA implementation recently as part of a problem, where we ar trying to allocate teams of an organization into different locations (we are a large company with many different team). The goal was to optimally allocate teams to individual buildings without putting too many teams into one building and not splitting teams apart.
    As we had around 400 teams of different sizes, solver couldn't handle it anymore. Luckily there is a Knapsack algorithm implementation in VBA readily available on the internet :).

    I also went with a heuristic approach first!

  5. Joe Egan says:

    An interesting mathematical solution but what if Eric and Xavier can't stand each other or Patrick is best friends with Steven - the real life problems that effect "even" teams.

    • Hui... says:

      @Joe

      You can add more criteria like
      If Eric and Xavier can't stand each other
      =OR(AND(E15=1,E16=1),AND(F15=1,F16=1),AND(G15=1,G16=1))
      It must be False

      If Patrick is best friends with Steven
      =OR(AND(E5=1,E17=1),AND(F5=1,F17=1),AND(G5=1,G17=1))
      It must be True

      Note that the 2 formulas above are exactly the same
      except for the ranges
      One must be True = Friends
      One must be False = Not Friends

  6. Gustavo Sousa says:

    Nice post Hui!

    I download your workbook and just try to change in options the Precision Restriction from 10E-6 to 10-8 and the Convergence from 10E-4 to 10E-10. The process take almost the same time, but the results was great.

    The standard deviation I got was 0,000471.

    Team 1: John, Tom, Kenny, Frank, Eric, Xavier, Edward, Zane
    Team 2: Steven, Hugo, Ben, Joe, Josh, Oliver, Cameron, William
    Team 3: Barry, Henry, Michael, Kyle, Patrick, Charles, Andrew, Lachlan

  7. Charlie says:

    Great application of Solver! Thanks for the link!

  8. Chuck says:

    Great explanation. Well done... However, I tried with 6 teams of 4 players and solver never did finish.

  9. Akbar says:

    How about vba code for the same data set.
    I have 3 column A B C wherein A has text and B has number Wherein C is blank. And in C1 been the header C2 where I want the name to come evenly distributed the number which is in Column B.
    My Lastcolumn is 1000.

  10. HRMFT says:

    Sorry if I'm being slow here, but how is 'Team Score' calculated? I've gone through the explanation several times but it seems to just appear.

    • Hui... says:

      @Hrmft

      This process uses the Solver Excel addin

      Solver is effectively taking the model and trying different solutions until it gets a solution that meets all the criteria
      Then solver puts the solution into the cell and moves to the next cell

      So yes it appears to "just appear"

  11. Caroline says:

    Hi ! Thank you so much ! Works great 🙂

  12. Jim Cruse says:

    I cannot get the fourth Equation to work in my excel spreadsheet
    You have =($E$2:$G$25=0)+($E$2:$G$25=1)=1 as a SUMIF solution, I have, =($F$2:$H$13=0)+($F$2:$H$13=1)=1 as my solution but it does not work. The only thing I changed is the ranges. Any suggestions?
    Thank you.
    Jim

  13. Jim Cruse says:

    I cannot get the fourth Equation of TURE or FALSE statements to work in my excel spreadsheet You have =($E$2:$G$25=0)+($E$2:$G$25=1)=1 as a SUMIF solution, I have, =($F$2:$H$13=0)+($F$2:$H$13=1)=1 as my solution but it does not work. The only thing I changed is the ranges. Any suggestions?
    Sorry I left some of it out in the previous question,
    Thank you. Jim

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