Advanced Data Validation Techniques in Excel [spreadcheats]

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Data validation is a great way to keep your users informed about possible values in a cell and guide them to select something appropriate. As part of the spreadcheats series, in this post we will discuss 2 advanced data validation techniques that can help you when you are modeling a complex worksheet.

Problem 1: You have 2 lists of possible values and you want a way to switch between both

PS: Many thanks to Alex who proposed this idea and solution through e-mail.

You have a cell where user can enter any value from 2 lists. But you don’t want to overload the in-cell drop down list with tons of values, and rather prefer a simpler approach like this:

data-validation-switch-lists

Solution: Use an IF() formula in validation criteria

validation-criteria-if-formulaThe solution is to use an if() formula to determine which one of the two ranges should be used to validate cell contents.

  • Select the cell where you want to have this type of validation
  • Go to menu > data > validation
  • In the criteria area, select “allow” as “list”
  • In the source area, specify a formula like this: =IF($B$7="Full List",Full-list-range,Partial-list-range)

That is all, you now have a data validation list that can change its source based on user preference.

Problem 2 : You would like to change a list’s values based on what is selected in another list

data-validation-change-listsPS: Many thanks to Catherine for asking this question through email

You have a status tracking spreadsheet where each employee enters the status for each of the projects they are working on. They enter the status by first selecting the department and then selecting a project (from that department).

So how do you do this in Excel?

Solution: Use OFFSET and MATCH to determine which range to use

Remember the offset() and match() formulas we discussed in the last spreadcheats?  Assuming the list of projects for each department is in a range B10:C22 with column B having the department name and column C having the project name and the list is sorted on column B, we can use offset() and match() combination along with countif (ahem!) to determine which range to use for project cell drop-down.

  • For the department cell, we can use simple list validation with values as “Marketing, Ops, Sales, IT”
  • For project cell, go to data validation (menu > data > validation) and specify a formula like this:
    =OFFSET(C9,MATCH($B$6,$B$10:$B$22,0),0,COUNTIF(B10:B22,$B$6),1)
  • What is above formula doing? It is fetching a sub-range from the by finding where the first entry for the selected department is, returning x number of rows from that point, where x = no. of projects in that department.

That is all. You now have a list drop-down that changes values based on what is selected in an earlier cell.

Still having doubts?

Feel free to download this example workbook containing a tutorial on Advanced Data Validation in Excel and poke around to learn.

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22 Responses to “Formula Forensic No 019. Converting uneven Text Strings to Time”

  1. Joe Carsto says:

    Why not let the TIME function take care of the math:
    =TIME(LEFT(TEXT(A1,"000000"),2),MID(TEXT(A1,"000000"),3,2),RIGHT(TEXT(A1,"000000"),2))

    • Ben Niebuhr says:

      I was going to point out the same thing, except to note that useing the time function and doing the divide method are not interchangeable.

      I have spent hours investigating a spreadsheet working with a couple of years worth of hourly data, and found that the reason things weren't working is because the rounding on the divide method is only close to the correct time values. In order to have it work for comparisons, (like sub-totaling by time value, or pivoting) you MUST use the TIME function.

      Great use of the TEXT function, Hui. I will be using this concept for sure.

  2. Elias says:

    Why not just.

    =TEXT(A1,"00\:00\:00")*1

    Regards

    • Joe Carsto says:

      Elegant!

    • Manick says:

      Hi Elias,

      I tried to use your formula. But, it doesn't seem to work for me. I am getting an error message "The formula you typed contains an error". It seems I have the problem in using \: in the format. How can I overcome this?

      Thanks

      • Greg G says:

        Manick, it isn't the /: that causes the problem. If you copy/paste it, you're getting “'s instead of the actual quotation marks that Excel uses. Change the quotation marks by deleting from the pasted formula and retype them.

      • modeste says:

        Hi Manick...
        use this alternate formula :
        =1*TEXT(A1,"00"":""00"":""00")

        note twice double quote each side of :

  3. Elias says:

    @Manick,

    Did you copy the formula and pasted in Excel or did you typed? Also, do you use , or ; as separator of arguments?

    Regards

    • Joe Carsto says:

      @Elias: I had no problem using your formula, in fact, I have used your method to convert a number such as 20120419 to an Excel date using =TEXT(A1,"0000\/00\/00")*1. Thanks for posting.

      • Elias says:

        @Joe: For date convertion you can use this as well.

        =TEXT(A1,"00-00-00")*1

        Regards

        • Joe Carsto says:

          Sweet! It appears this also works with =TEXT(A1,"0-00-00")*1. I come from the old days when you counted every byte. I also like to try an make formulas as small as possible for the fun of it 🙂

  4. Haseen says:

    Elias's suggestion is the simplest, but here is yet another way with TIME and MOD functions...

    =TIME(MOD(A2/10000,100),MOD(A2/100,100),MOD(A2,100))

  5. Since the seconds appear to always be 0, why not simply the input to minutes and above and save yourself the trouble of typing those zeroes...

    0 => 0:00
    1 => 1:00
    10 => 10:00
    100 => 1:00:00
    etc.

    Then just use this formula...

    =TEXT(A1,"0\:00\:")*1

    • Elias says:

      @ Rick, the numbers to convert are no typed, they are imported. Then your formula will return the wrong result.

      Regards.

  6. Hmm! My formula lost some backslash-zero combinations (two of them to be exact). The formula was supposed to be this...

    =TEXT(A1,"0\:00\:\zero\zero")*1

    where the words "zero" should actually be the number 0. Another way to write the formula is this...

    =TEXT(A1,"0\:00\:""00""")*1

  7. Rajagopal says:

    Hi Master,
    While writing the formulae you have considered only upto "seconds factor" . I think you should take the centi-seconds factor also to achieve best results. Please look into it and rectify the problem...?

    For Example.
    In horse racing timings are noted in minute, seconds and centi-seconds, like if a horse finished in 70 seconds over a scurry of 1200 metres, is noted as 1.10 min. Nowadays it is noted in centi-seconds everywhere, like 70.00 if you want to convert it to centi seconds (should multiply by 100) = 7000 centi seconds. If you put this figure into your formula as a general number (7000) it will return as 1:10:00. As per your formula, it should be taken as 1 hour 10 seconds 0 minutes. However for a racing enthusiast like me it can be taken as 1 minute 10 seconds also.

    Just look what happens if we race goers use this figure as 7000 centi seconds in your formulae, it will correctly show as 1 minute 10 seconds(?) Suppose a horse finishing over a 1200m in 70.60 seconds or in racing terms written as 1.10.60 mins, where 1 minute 10 seconds, & 60 centi-seconds can be counted as 7060, if you put this figure in the formula it will return as 1 minute 11 seconds, that is correct.

    My point is if you can incorporate Centi Seconds in the formulae, it would be of great help to us also.

    Thanks and regards.
    Rajagopal (Mumbai)

  8. Vishy says:

    Awesome techniques !

    I tried with 235960 just to see if it will fail but this is great.

  9. CMC says:

    Although a little longer, this too work:

    =CHOOSE(LEN(A2);A2/(24*3600);A2/(24*3600);LEFT(A2;1)/(24*60) + RIGHT(A2;2)/(24*3600);LEFT(A2;2)/(24*60) + RIGHT(A2;2)/(24*3600);LEFT(A2;1)/24 + MID(A2;2;2)/(24*60) + RIGHT(A2;2)/(24*3600);LEFT(A2;2)/24 + MID(A2;3;2)/(24*60) + RIGHT(A2;2)/(24*3600))

  10. Converting uneven Text Strings to Time I have imported some data that comes in as a number that I need to convert to h:mm.

  11. Sudhir Gawade says:

    Just come across this while googling

    find interesting challenge and come up with this 

    =TEXT(TEXT(SUBSTITUTE(A1,RIGHT(A1,1),""),"000000"),"00\:00\:00")

  12. Renee Keel says:

    I need to convert a string of numbers representing average minutes, to reflect correct time values. For example, the numbers below currently represent 5.79 minutes, 15.82 minutes, etc.

    I need to convert these values to their correct corresponding value within time parameters. So 5.79 would be something close to 5 minutes and 45 seconds.

    5.79
    15.82
    3.92
    12.40
    6.70
    3.62

    I know there has to be a way to compute this in Excel, it can do anything, I believe!

    Thank you for any and all assistance~

    • Chandoo says:

      @Renee... You can use a formula like this. Assuming A1 has the minutes.seconds,

      =INT(A1) + MOD(A1, 1)*0.6

      If you want to see it in 5 minutes 45 seconds format, use

      =INT(A1) & " mins " & ROUND(MOD(A1, 1)*0.6,2) & " secs"

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