# Calculating average of every nth value [Formula tips]

Lets say you have a large list of numbers, and you want to **calculate the average of every nth value**. Not the average of all numbers, but just every

*nth*number.

That is what we will learn in next few minutes.

### Few assumptions

Before we jump in to any formulas, first lets assume that all your data is in a table, conveniently named as *tbl.* Lets say this table has below structure.

Also, the value of n is a named cell **N**.

## Average of every nth value

### Approach 1: Using helper columns

If you have no allergies towards nuts, dairy or helper columns, then this approach is easiest.

We just add an extra column to our *tbl *, called as* helper.*

In the helper column, write this formula.

=MOD([@ID], N)=0

This will fill the helper column with TRUE & FALSE values, TRUE for all nth values, FALSE for everything else. See aside.

Once we have the helper column, calculating average of every nth value is easy as eating every slice of a cake.

We use AVERAGEIF to do this.

=AVERAGEIF(tbl[Value],tbl[Helper],TRUE)

### Approach 2: Not using helper columns

Now things get interesting. Lets say you want to calculate average, but not use any helper columns.

**First the formula:**

=AVERAGE(IF(MOD(tbl[ID], N)=0,tbl[Value]))

*Array entered.*

**Lets understand how it works:**

We want the average of every nth item of tbl[Value] column.

In other words, we want average of every item of tbl[Value] column, whose corresponding tbl[ID] value is *perfectly *divisible by n.

How do we know when a value is perfectly divisible by another?

Don’t worry. You don’t have to do the long division on paper now. Instead we use Excel’s MOD function.

When a value is perfectly divisible by another, the reminder is **zero.**

So, MOD(value1, value2) = 0 means, value2 divides value1 perfectly.

**That means…**

We want the average of tbl[Value] when MOD(tbl[ID], N) = 0

Lets write that in Excel formula lingo.

=AVERAGE( IF(MOD(tbl[ID], N) = 0, tbl[Value]) )

This formula results in a bunch of values and FALSEs. Assuming N=3, this is what we get (for sample data):

=AVERAGE({FALSE;FALSE;15;FALSE;FALSE;18;FALSE;FALSE;18;FALSE;FALSE;15;FALSE;FALSE;14; …})

Since AVERAGE formula ignores any logical values, it will calculate the average of {15, 18, 18, 15, 14 … } and returns the answer you are expecting.

As this formula is processing arrays instead of single values, you need to array enter it (CTRL+SHIFT+Enter after typing the formula).

### Bonus scenario: Average of FEBRUARY values only!

Here is a bonus scenario. Lets say you want to calculate the average sales of FEB alone… Then you can use AVERAGEIF (or AVERAGEIFS, if you want to have multiple conditions).

=AVERAGEIF(tbl[value], tbl[month], “FEB”)

## Download example workbook:

**Click here to download the example workbook**. It contains all the techniques explained in this post. Play with the data & formulas to understand better.

### Time for some challenges…

If you think averaging every nth value is not mean enough, try below challenges. Post your answers using comments.

- Write a formula to calculate average of every nth value,
.**starting at row number ‘t’** - Write a formula to calculate average of every nth value, assuming your table has only value column (no ID column).

Go ahead. Show off your formula skills. Post your answers in comments section.

### Improving your Excel batting average

Calculating averages predates slice bread. Folklore says that when first neanderthal figured out how to express numbers and carved 2 of them on a cave wall, his manager walked by and asked “What is the average of these two? Eh?” and thumped her chest.

Although caves & wall carvings are replaced by cubicles & spreadsheets, we are still calculating averages, almost 2.9 million of them per hour.

So it pays to learn a few tricks about Excel Average formulas. Check out below to improve your average:

- Calculating Moving Average, Weighted Average
- Average of top 5 values
- Show averages & distribution in your charts
- Using SUMIFS formula (same tricks apply to AVERAGEIF, AVERAGEIFS too)

If your boss is the kind who thumps her chest and mocks you for your poor Excel skills, don’t cave in. Fight back. **Enroll in Excel School** and show that you can evolve.

### Leave a Reply

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## 16 Responses to “Calculating average of every nth value [Formula tips]”

I think the helper column can be replaced by a ROW function:

=AVERAGE(IF(MOD(ROW(tbl[Value])-ROW(tbl[[#Headers],[Value]]),$G$5)=0,tbl[Value]))

(array entered)

and including every nth value after row t (specified in cell H5):

=AVERAGE(IF((MOD(ROW(tbl[Value])-ROW(tbl[[#Headers],[Value]]),$G$5)=0) * (ROW(tbl[Value])>=H5),tbl[Value]))

(array entered)

Don't know if there's a shorter version I'm missing here π

=AVERAGE(IF(MOD((ROW(tbl)-ROW(tbl_start)),N)=0,tbl))

Array Enter

assume tbl has a header, and "tbl_start" refers to the cell of the header

"If you think averaging every nth value is not 'mean' enough" π

Here's a non array formula version that can be used with any range of values and any value for N:

=SUMPRODUCT(--(MOD(ROW(ValRange)-CELL("row",ValRange)+1,N)=0),ValRange)/INT(ROWS(ValRange)/N)

I'm sure there's a way to shorten this, but just my first attempt!

I have combined both part (starting at row number T and not using helper column) [G2 has the value of T]

=IFERROR(SUMPRODUCT(INDEX(tbl[Value],G4):INDEX(tbl[Value],COUNT(tbl[Value]))*(MOD(ROW(INDIRECT("1:"&COUNT(tbl[Value])-G4+1)),G5)=0))/INT((COUNT(tbl[Value])-G4)/20), "Out of list Range")

Hi Chandoo, I want to know, why the formula "averageifs" can't be replaced by "averageif". It seems that there is just one criteria required to the calculation, no need to use the formula "averageifs".

They both work Legei. I have used AVERAGEIFS as it will let you add more conditions if needed.

Hi Chandoo,

Strangely Approach 1: AVERAGEIF(tbl[Value],tbl[Helper],TRUE) is not working for me as well.

Whereas if you use AVERAGEIFS, the function is working fine. Can you please double check if it (AVERAGEIF) works for you?

Thanks!!

PSG

Use AVERAGEIF(tbl[Helper],TRUE,tbl[Value])

[…] Calculating average of every nth value […]

How might one perform this function with the following restrictions:

1) the table has no ID column, rather just a single column of values, and

2) the table does not start conveniently at cell A1, but rather in a random place on the worksheet?

I don't understand the [@id] notation, can you point me to something that clarifies?

When I recalculate the excel file for the*=AVERAGE(IF(MOD(tbl[ID],$G$5)=0,tbl[Value]))*, the value become zero, and the evaluation of the formula become AVERAGE(IF(MOD(1,20)=0,tbl[value])).

And further evaluation give AVERAGE(IF[FALSE,tbl[value]).

I really don't know how to fix this problem.

P.S I am using EXCEL 2010

+AVERAGE(MOD(ROW(INDIRECT("1:"&COUNT(a_list))),3)=0,a_list)

with ctrl + shift + enter

I think this works ?

+AVERAGE(MOD(ROW(INDIRECT(β1:β&COUNT(a_list))),n)=0,a_list)

i had checked my formula with 3 and hence put 3 in my previous post

in colum A i have 1000(values) rows i want to take an average of every 10 values (in colum) . so that it will give me 100 values in colum b. can any Body tell me how can i do that.

please tell me most simple way to do that.

do i have to define macro for that (hope fully not) i have Excel 2010