I am fascinated by board games. They provide immense fun, anyone can enjoy them, they are unpredictable and best of all they are great value for money. That is why whenever I get sometime I experiment with simulating games to know them better [read Why Monopoly board game is not as random as it appears]. So, out of curiosity I have created an excel sheet that can generate bingo / housie (housey) tickets – 24 of them at a time. To get new set of tickets you would hit F9 (recalculate).
Click here to download the bingo / housie ticket generator.
Note that these are Bingo UK / India / Australia variant I am talking about, not the US 5*5 type of bingo tickets.
Read on if you want to know how this is done:
According to Wikipedia:
A typical housie/bingo ticket .., contains fifteen numbers, arranged in nine columns by three rows. Each row contains five numbers and four blank spaces. Each column contains either one, two, or very rarely three, numbers:
* The first column contains numbers from 1 to 9,
* The second column numbers from 10 to 19,
* The third 20 to 29 and so on up until the last column, which contains numbers from 80 to 90.
I have removed number “90” from the list in order to reduce some complexity in generating the tickets.
The problem is now to “generate 15 random number between 1 to 89 and fill them in 15 random spots in a grid of 3 rows by 9 columns such that each row has exactly 5 numbers”
Now I could write a function in VBA to do this, but I wanted to do this only using formulas. So I started breaking the problem.
The first challenge is to select any random 5 cells in a 9 cell row
Once we select any random 5 cells in a 9 cell row, we will fill them with bingo numbers. Now, excel has a function to generate random numbers between 1 to 9 (=round(rand()*9,0)), but this is not good for us since each time we call this function we will get a random number between 1 to 9, where as we need a 5 random numbers without repetition between 1 to 9. The function is memoryless and could repeat numbers when called 5 times.
Instead we can list all the possible “5 cells with numbers and others are empty” combinations of a 9 cells region and select a random combination every time. There are essentially 9C5 i.e. 126 ways in which you can select any 5 cells out of 9 cells (without repetition of course).
So I listed all these combinations in a table and then randomly selected one of the combinations. You can see the first five such combinations in the image below:
Selecting any five cells out of nine cells
Now I created a 3*9 region and filled the cells with 1s or 0s, “1” when the cell in bingo ticket is supposed to have a value and “0” if the cell is empty as shown below:
Next challenge is to show random values in each cell
The trick here is that first column in our 3*9 bingo ticket has any number(s) from 1 to 9, second column has any number(s) from 10 to 19 …
Again, the challenge is the numbers should not repeat, otherwise we could simply use rand()*10, rand()*10+10, rand()*10+20 ... to generate the numbers.
This time it gets even more trickier because each column can have either no values, or 1 value or 2 values or 3 values.
The ticket generation logic now looks like:
- If the column has no values in it, then we will leave all the cells in that column of bingo ticket empty
- If the column has 1 value, we will generate any random number from that column’s range of possible values (1-9, 10-19,20-29,…80-89) and place it in the cell that is supposed to have a value and leave other cells empty.
- If the column has 2 values, we will generate 2 random numbers without repetition from that column’s range of possible values and place them in cells that are supposed to have them
- If the column has 3 values, we will generate 3 random numbers without repetition from that column’s range of possible values and place them in cells that are supposed to have them
As you can see, it is easy when the column has no or 1 value in it. But when the column has 2 or 3 I used the combinations trick described earlier.
First I created all 2 number combinations and 3 number combinations. Since the numbers on Bingo ticket are always sorted from top to bottom in a column, I just had to list down 45 combinations (10C2) for 2 numbers and 120 combinations (10C3) for 3 numbers.
The rest of the details are small enough that I can leave them to your imagination. So when the ticket is generated, it looks like this:
Remember to download housie / bingo ticket generator excel sheet and print your tickets at home. Just F9 to generate new set of tickets. Un-hide the rows from 43 if you want to see how this is done.
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20 Responses to “Untrimmable Spaces – Excel Formula”
Hi Chandoo,
First of all, HAPPY NEW YEAR!!! Wish you and your family another fruitful year ahead.
To answer your question: Power Query is the best way to trim. 🙂
Btw, if Power Query is not available, then formula would absolutely do... but did you forget to mention also Char 32?
One more question: Is the trailing minus meant to be a negative number? Maybe only the sender knows... 🙂
Cheers,
I just see your PQ way, it is amazing, I think it is the most simple way.
No idea how it did it?
I know these spaces can be a real pain but these days I advise Excel users to learn and use Flash Fill and that will learn what to do pretty quickly.
Highlight range to be cleaned. Then, in Replace, hold down the Alt key and type 0160. Replace with nothing.
I accomplished this by writing a macro to go through all the possible unprintable characters. Looped through the range.
@Steve
Brute force works just as well, its just slower
I use a different method here. First, I will copy the data from Excel and paste it in a notepad. In Notepad, I will do a Find Blanks (Space " ") and Replace (Empty) with nothing.
Then you can copy the data from Notepad and paste it back to Excel which will be a perfect number as you desire.
But Thanks for the formula. Its probably the 2nd out of 8 tricks as Chandoo mentioned. Waiting for the rest among 8 from other users 🙂
Hi....
You don't always need notepad for that. I use the Find/Replace is Excel works just fine.
I don't understand the x's. Why weren't they removed in the formula? Or are they part of some sort of numeric formatting that I'm not familiar with? I saw how you handled the non-breaking spaces and the dashes, but am confused about what role the x's played in all this.
Thanks!
Hi Andrew ,
The xs have been used solely to demarcate the actual data text ; thus , without the x in place at the end of text , as in :
x 4,124,500.00 x
it would be impossible to know that there are unwanted trailing characters , in this case , after the last 0.
These xs are not part of the original data text , nor are they used in the formulae ; they are put in only so that readers can visualize the individual items of data as they are in practice. Think of them as imaginary delimiters.
Oh, that makes sense! Thank you for the explanation. I had a feeling it was something along those lines.
You can type this character using the Keys Alt+0160.
Very useful to replace this Character using Find and Select resource.
For many years, my jobs have included ETL tasks and I built this macro to help long, long ago. I tweak it every now and again. Many co-workers, past and present, have it wired to a button on their toolbar.
Sub Clean_and_Trim()
'CAUTION: Strips leading zeroes -- do not use on zipcodes, etc.
If Application.Calculation = xlCalculationAutomatic Then
Application.Calculation = xlCalculationManual
Revert = 1
ElseIf Application.Calculation = xlCalculationManual Then
Revert = 0
End If
For Each Cell In Selection
For x = Len(Cell.Value) To 1 Step -1
If Asc(Mid(Cell.Value, x, 1)) = 160 Then
Cell.Replace What:=Chr(160), Replacement:=" ", LookAt:=xlPart, MatchCase:=True
End If
If Asc(Mid(Cell.Value, x, 1)) = 32 Then
Cell.Replace What:=Chr(32), Replacement:=" ", LookAt:=xlPart, MatchCase:=True
End If
Next x
If Cell.Value "" Then
Cell.Value = Application.Clean(Application.Trim(Cell.Value))
End If
Next
If Revert = 1 Then
Application.Calculation = xlCalculationAutomatic
ElseIf Revert = 0 Then
Application.Calculation = xlCalculationManual
End If
End Sub
This is awesome! What if you have several characters you need to have removed? What would be the easiest way as I can imagine there are several ways.?
# - 35
$ - 36
- 62
/ - 47
, - 44
. - 46
" - 34
: - 58
This is typical case of a Fitbit data export to Csv file. Each number has CHAR160 as thousand separator.. how smart Fitbit, thank you 😉
By the way, i prefer to copy the character, and use find and replace.
Sometimes it happens if you copy a table from outlook and paste it in excel. When you apply formula on those cells you will get error. What i use to do is
copy one character that looks like space,
select the entire range,
go to Find and replace,
Paste the copied character in Find option
Leave the replace option unfilled..
click on replace all..
All the errors shall be converted in to proper values..
Process looks lengthier.. but it is one of the simplest method
If Clean, Trim, and Substitute, or Find and Replace does not complete the job, I usually enter a value of 1 in an empty cell. Copy the Value of 1, Highlight the range of text numbers, and Paste Special, Values, Multiply. This site is great!
You can use Dose for Excel Add-In that can quickly clean huge data with one click besides more than +100 new functions and features to add to your Excel to save time and effort.
https://www.zbrainsoft.com
Hi,
I have a problem in excel. The sheet attached herewith.
TABLE CONFIG 2/6
A B C D E F G H
1 WEIGHT1 43,599 WEIGH2 62500 WEIGHT3 77000 WEIGHT4 66,500
2 DEDUCTION1 15,000 DEDUCTION1 15,000 TEMP 0 DEDUCTION2 11,005
3 RESULT 58,599 RESULT-1 77,500 RESULT-2 77,000 RESULT-3 77,505
4 RESULT SUBSTRACT 0 0 0
5 REQUIRED VALUE 77,500 77,000 77,505
Note: 1- RESULT (58599) IS TO BE DEDUCTION EITHER FROM D4 OR F4 OR H4 WHICHEVER IS MOST
LEAST CELL AMONG RESULT-1 OR RESULT-2 OR RESULT 3.
2-HENCE, RESULT VALUE $B$3 IS TO BE PRESENTED ON CELL EITHER D4 OR F4 OR H4 WHICHER IS
MOST LEAST VALUE
3-FORMULA =IF(E8<H8,$B$9,IF(E8<J8,$B$9,IF(H8<J8,$B$9,IF(H8<E8,$B$9,IF(J8<H8,$B$9))))))
CREATED ON CELL D4,F4 & H4 DID NOT WORK.
PLS FOR YOUR HELP.
THANK YOU
@R
Why not ask the question in the Chandoo.org Forums
https://chandoo.org/forum/
You can attach a file there