I am fascinated by board games. They provide immense fun, anyone can enjoy them, they are unpredictable and best of all they are great value for money. That is why whenever I get sometime I experiment with simulating games to know them better [read Why Monopoly board game is not as random as it appears]. So, out of curiosity I have created an excel sheet that can generate bingo / housie (housey) tickets – 24 of them at a time. To get new set of tickets you would hit F9 (recalculate).
Click here to download the bingo / housie ticket generator.
Note that these are Bingo UK / India / Australia variant I am talking about, not the US 5*5 type of bingo tickets.
Read on if you want to know how this is done:
According to Wikipedia:
A typical housie/bingo ticket .., contains fifteen numbers, arranged in nine columns by three rows. Each row contains five numbers and four blank spaces. Each column contains either one, two, or very rarely three, numbers:
* The first column contains numbers from 1 to 9,
* The second column numbers from 10 to 19,
* The third 20 to 29 and so on up until the last column, which contains numbers from 80 to 90.
I have removed number “90” from the list in order to reduce some complexity in generating the tickets.
The problem is now to “generate 15 random number between 1 to 89 and fill them in 15 random spots in a grid of 3 rows by 9 columns such that each row has exactly 5 numbers”
Now I could write a function in VBA to do this, but I wanted to do this only using formulas. So I started breaking the problem.
The first challenge is to select any random 5 cells in a 9 cell row
Once we select any random 5 cells in a 9 cell row, we will fill them with bingo numbers. Now, excel has a function to generate random numbers between 1 to 9 (=round(rand()*9,0)), but this is not good for us since each time we call this function we will get a random number between 1 to 9, where as we need a 5 random numbers without repetition between 1 to 9. The function is memoryless and could repeat numbers when called 5 times.
Instead we can list all the possible “5 cells with numbers and others are empty” combinations of a 9 cells region and select a random combination every time. There are essentially 9C5 i.e. 126 ways in which you can select any 5 cells out of 9 cells (without repetition of course).
So I listed all these combinations in a table and then randomly selected one of the combinations. You can see the first five such combinations in the image below:
Selecting any five cells out of nine cells
Now I created a 3*9 region and filled the cells with 1s or 0s, “1” when the cell in bingo ticket is supposed to have a value and “0” if the cell is empty as shown below:
Next challenge is to show random values in each cell
The trick here is that first column in our 3*9 bingo ticket has any number(s) from 1 to 9, second column has any number(s) from 10 to 19 …
Again, the challenge is the numbers should not repeat, otherwise we could simply use rand()*10, rand()*10+10, rand()*10+20 ... to generate the numbers.
This time it gets even more trickier because each column can have either no values, or 1 value or 2 values or 3 values.
The ticket generation logic now looks like:
- If the column has no values in it, then we will leave all the cells in that column of bingo ticket empty
- If the column has 1 value, we will generate any random number from that column’s range of possible values (1-9, 10-19,20-29,…80-89) and place it in the cell that is supposed to have a value and leave other cells empty.
- If the column has 2 values, we will generate 2 random numbers without repetition from that column’s range of possible values and place them in cells that are supposed to have them
- If the column has 3 values, we will generate 3 random numbers without repetition from that column’s range of possible values and place them in cells that are supposed to have them
As you can see, it is easy when the column has no or 1 value in it. But when the column has 2 or 3 I used the combinations trick described earlier.
First I created all 2 number combinations and 3 number combinations. Since the numbers on Bingo ticket are always sorted from top to bottom in a column, I just had to list down 45 combinations (10C2) for 2 numbers and 120 combinations (10C3) for 3 numbers.
The rest of the details are small enough that I can leave them to your imagination. So when the ticket is generated, it looks like this:
Remember to download housie / bingo ticket generator excel sheet and print your tickets at home. Just F9 to generate new set of tickets. Un-hide the rows from 43 if you want to see how this is done.
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21 Responses to “Distinct count in Excel pivot tables”
The distinct count option works well but I have found that if I have a date field and want to group by year, month, etc. that option seems to be disabled. I need to do both, distinct count and group by year/month.
Example data; sales orders with item quantities with dates.
Challenge; sum the item quantities, count the distinct orders and group by month. How do I do this?
Perhaps that's not possible due to the grouping?
@Al... When you use data model based pivots, you cannot group values manually anymore. Why not use Excel 2016's default date grouping option? In this case we have just a few dates, so Excel is not grouping them, but if you have an year's worth of data, when you make the pivot with date in the row label area, Excel automatically groups them. If you have fewer dates or want to use your own grouping, just create a table with all dates, add columns with month, week, year etc. Then connect this table (these types of tables are usually called as calendar tables) to your data on date field as a relationship. Now you can create reports by month, quarter etc easily.
Is this the only way to do it in 2013? I find it rather cumbersome to have to create another data table listing dates with the another column for MONTH() and YEAR() to be able to summarise data for senior level...
I know people find adding calendar tables cumbersome, but it is a best practice and let's you add more layers of analysis quite easily. For example, adding analysis by weekday vs. weekend or by financial quarter or YTD calculations (you would need either Power Pivot DAX or some very carefully setup pivot table value field settings)
I had absolutely no idea this was possible. Very useful, nice work!
Doesn't work for 2010 version though (or at least not my works version)
Hi ,
The post has the following in it :
These instructions work only in Excel 2016, Office 365 and Excel 2013.
when i have 2 different Pivot tables, one without the enabled “Add this data to data model” option, and the other one with it enabled.. is there anyway i can link slicers between them?
if the answer is NO,, what to do ?
Quick note, the “Add this data to data model” option is not available for the Mac version.
perhaps outside scope of this article but I have found when I attempt to create a pivot table from an external data source (connection to a sql view) the "Add this data to data model" becomes greyed out. Anybody experienced and found a solution so I can start getting distinct count in my pivot tables?
Is there a way to still add a calculated field when using distinct count?
I found I can't change the date source after tick the " add this data to the data model", can you help to adv how to change the date source in such case?
Is there a way to update the source once you have added to the data model? I receive a new spreadsheet weekly and would like to update the connection so my tables pull from the new source.
Hi Crhis, I like how you have hulk (superhero) as your avatar. Do you know that there is a superhero in Excel too? It's Power Query. You can use it to solve your problem in a simple click. Here an intro if you need some guidance.
Powerful Introduction to Power Query
A big Thank you. It worked.
Hi, have survey data that I need to analyze but the challenge is that my key fields are showing horizontally. I tried to transpose the fields using Power Query, but unfortunately the new fields are returning same values on a pivot table despite using distinct values
How I can a do a pivot table with discount conts in some columns and then generate shor report filter pages. pls it drives crazy
Hi. Why grand total pivot of distinct count is 13? shouldn't it be 67?
Great Answer! Saved me lots of time!
Thank you!!!
Worked awesome! Thanks!!
Hi Chandoo,
I am using pivot tables for distinct count and now I need to update them with new set of data. But when I update the source data, all the columns and formatting of Pivot table disappears and I need to build it from Scratch.
Is there a possibility that I can update the source data with new rows added and also retain my pivot tables?