VLOOKUP is one of the most useful Excel functions. So much so that I even wrote a book about it. But it has one serious limitation.
It looks up the first occurrence and returns corresponding data.
What if you want to find the last value?
Say, for example, you are looking at a task assignment list and want to know what is the last task assigned to employee Emp13?
We want to extract the task “Make amazing workbook”. Of course our good old VLOOKUP stops once it finds Emp13 and returns the answer as “Create intuitive workbook”.
Let’s learn the formulas required to lookup last value.
VLOOKUP last value
Although I said VLOOKUP last value, we can’t use VLOOKUP formula to do this. Not unless we add a helper column to the original data (or come up with a long array formula version of VLOOKUP). So, instead we are going to use other Excel formulas to find the answer.
2 parts of the problem
There are 2 parts of the find last value problem.
- Find the position of last occurrence of given employee (for ex. Emp13’s position would be 5
- Return corresponding details (task description, due date or completion status)
Let’s attack each part.
1. Finding the last occurrence position
First take a look at the array formula.
=MAX(ROW(tasks[Employee])*(tasks[Employee]=lookup.value)) - ROW(tasks[[#Headers]])
Remember to press Ctrl+Shift+Enter after typing this.
This array formula returns the position of lookup.value in the list.
How does this formula work?
Let’s go inside out.
(tasks[Employee]=lookup.value) portion:
This will return a bunch of TRUE / FALSE values by checking each item of tasks[Employee] list against lookup.value.
For lookup.value=Emp13, we get below array:
{FALSE;FALSE;FALSE;TRUE;TRUE;FALSE;FALSE;FALSE; FALSE;FALSE;FALSE;FALSE;FALSE;FALSE; FALSE;FALSE;FALSE;FALSE;FALSE;FALSE;FALSE;FALSE;FALSE;FALSE; FALSE;FALSE;FALSE;FALSE;FALSE;FALSE}
ROW(tasks[Employee]) portion:
This will return a bunch of running numbers starting with row number of first item in the tasks[Employee] list.
For our data, we get this:
{5;6;7;8;9;10;11;12;13;14;15;16;17;18;19;20;21;22;23;24;25;26;27;28;29;30;31;32;33;34}
ROW(tasks[Employee])*(tasks[Employee]=lookup.value) portion:
This just multiplies the row number array with boolean values, returning an array with 0s for all row numbers except where we have lookup.value as Employee. For lookup.value=Emp13, we get this:
{0;0;0;8;9;0;0;0;0;0;0;0;0;0;0;0;0;0;0;0;0;0;0;0;0;0;0;0;0;0}
MAX (ROW(..) * (...)) portion:
This will tell us the maximum row number where lookup.value occurs in tasks[Employee] list.
So we get 9 as answer.
MAX (...) - ROW(tasks[[#Headers]]) portion:
As our data doesn’t begin on row 1, we need to subtract the header row position from MAX(…) result. To get the header row number, we are using ROW(tasks[#Headers])
In the end we get the result as 5.
Let’s assume this result is in a cell named last.lookup
2. Return corresponding details
Now that we know the position of last lookup value, we can use INDEX formula to get corresponding details.
So to get the task description, we can use =INDEX(tasks[Task], last.lookup)
And to get the due date, we can use =INDEX(tasks[Due by date],last.lookup)
A twist – VLOOKUP latest value
Now, time for a twist. What if you want to find the latest value by looking at another column like Due by date. In other words, we want to find the latest task for Emp13.
That is your homework. Go ahead and figure out the formula. Once you have answer, post it in comments.
Download VLOOKUP last value example workbook
Please click here to download VLOOKUP last value example workbook. Examine the formulas to understand this technique.
PS: You can find one solution for this problem in downloadable workbook.
24 Responses
I’d suggest simply using the subtotal function and filtering the data using the Win/Loss column. You get the same results and the formula is more comprehensible.
@John
That is one option.
There are times however when you want to see the whole data table or a filtered subset and still want to produce summary reports against an unfiltered field.
Is there a particular reason why you are using a comma and the unary (–) operator for the second array in the SUMPRODUCT formula? It seems to work the same if you were to string the arrays together using the asterisk (*). The advantage is that SUMPRODUCT treats the entire string of arrays as a single array.
@Mathew
Your correct, There is no difference.
I thought it may have been easier to explain this method.
Is there a way to do this on a large set of data? As in ~100,000 rows? When I try I get an error because the formula becomes too long. It says the max length of a formula is 8,192 characters. Excel 2010.
How do I incorporate a specific text within a cell for the second array. For instance, – -(C7:C13=”Apple”)
when I chose a specific text the formula does not work.
@RB
I am not sure what is the issue as if I use the sample data in the post the following work fine
Count:
=SUMPRODUCT(SUBTOTAL(3,OFFSET(C7:C13,ROW(C7:C13)-MIN(ROW(C7:C13)),,1)), –(C7:C13=”L”))
Sum:
=SUMPRODUCT(SUBTOTAL(3,OFFSET(C7:C13,ROW(C7:C13)-MIN(ROW(C7:C13)),,1)),(C7:C13=”L”)*(D7:D13))
You may want to check that there are no leading or trailing spaces in your list of Apples
I should have given a better explanation. Heres my situation. I have a column with cells filled with names like Column 1, Column 2, Pier 1, Pier 2, etc. If the cell just contained Pier and searched for that it works. But because it has other characters in the cell its not recognizing the pier. So how can I extract specific characters of a string of text in this formula?
Hopefully this was a better explanation
Hello-
This formula works pretty well for me except that it slow down excel and prevents some of my macros from working. I was wondering if there was a way to program this in VBA so that excel isn’t always trying to recalculate it. I would like to use a push of a button to get it to run then paste in a cell.
Thanks!
I am trying to sum filtered data in a column, but would want to ignore the negative values in the column. How to go about doing this?
@Akshay
Why not just add a filter to that column to only show the values greater than zero?
The negative values are required for reporting purposes, but their effect on the total is distorting the required output. Please advise.
@Akshay
I’d suggest making a post in the Chandoo.org Forums
http://forum.chandoo.org/
Attach a sample file to simplify the task
I have this working for counting and summing, however, I have a list and for the second array, I need a criteria. That is, I’m looking for b13:b200=”01.??.??” or =left((a1,2) or something like that. These types of criteria matches do not appear to work as I get a blank as a result.
Thanks!
@Bob
As your formula b13:b200=”01.??.??” looks like you are trying to check the first day of the month of the range
What about trying Day(B13:B200)=1
Hai Experts,
i understood this formula well and working fine in MS Excel 2013
but when the same am trying to place in google Spreadsheet it shows error as
“SUMPRODUCT has mismatched range sizes. Expected row count: 1. column count: 1. Actual row count: 2014, column count: 1.” and as a result #VALUE! Appears in cell.
Can anyone please help me how would i get it done in Google Spread sheet
or is there any other formula as a substitute for this.
Thank you very much.
thanks for providing this.. but why does excel keeps on prompting Circular referencing in cell D3?
@Vivek
I don’t know
I just downloaded the file and it is working fine and not showing that error
Goto the Formulas, Calculation Options Tab and check that Calculation is set to Automatic
What version of Excel and Windows are you using ?
I know that this forum is for MS Excel, but I am trying to help someone who is working in Google Sheets. The below formula works in Excel but Google Sheets returns:
“SUMPRODUCT has mismatched range sizes. Expected row count: 1. column count: 1. Actual row count: 39000, column count: 1.” and as a result #VALUE! Appears in cell.
This is the same problem asked by Srichirin above. Does anyone know if there is a formula for Google Sheets that will replicate what MS Excel does?
=SUMPRODUCT(SUBTOTAL(3,OFFSET($C$6:$C$39500,ROW($C$6:$C$39500)-MIN(ROW($C$6:$C$39500)),,1)),- -($C$6:$C$39500=H1),($D$6:$D$39500))
Trying to find a SUMPRODUCT formula that counts the word Closed by date for the last 7 days in a filtered list.
=COUNTIF(M:M,”>”&TODAY()-7) works ok for unfiltered count Column M contains Closure dates (blank if open) and Column L is Status Open or Closed
@ Terry
Please ask the question at the Chandoo.org Forums
https://chandoo.org/forum/
Please attach a sample file to ensure a quicker more accurate answer
I used this formula and worked like a charm! But, now I’ve been requested to use it but adding not one but two criteria in the same formula. For instance the sum I was doing added negative and positive numbers. I’ve been asked to use the exact same formula but adding that only positive numbers were considered… any idea on how to do this?
How exactly do you do sum filtered cells when two criteria are need not just one?
Thank you so much brother literally I have been struggling since morning to get the sum of the filtered category, however, after reading your blog attentively i got my solution, so thanks a lot once again.