We all know that networkdays() an extremely powerful and simple excel formula can help you calculate no. of working days between 2 given dates.
But there is one problem with it. It assumes 5 day workweek starting with Monday to Friday. Not all countries have workweek from Monday to Friday. As Incubus wrote to me in an e-mail,
In Excel, the function “networkdays” doesn’t work for users in the middle east ‘cos it counts Saturday & Sunday as weekend. This is good enough only if you live in elsewhere, but for us weekend is Friday & Saturday.
This got me thinking and I ended up writing a user defined formula (UDF) to calculate working days between 2 given dates with any criteria. This will be good for calculating payrolls for temporary workers, offshore partners and of course people working countries where Saturday or Sunday or not usually holidays.
Please download the NetWorkingDays Add-in if you want to use this function.
If you are curious what is inside, see the UDF code
How to use the NetWorkingDays() UDF?
Once you download the add-in, just install the add-in by,
- [in Excel 2003] By going to Tools > Addins > Browse
- [in Excel 2007] By going to Office Button > Excel Options > Addins > “Go button” > Browse
- Specify the location where you saved the downloaded file
Now that the add-in is installed, you can use the UDF by writing a formula like this:
=networkingdays("01-06-2009","02-07-2019","12356")
The first argument is start date, the second one is end date and third one tells which days of week are working (Monday is 1 and Sunday is 7). So the above formula counts all the Mondays, Tuesdays, Wednesdays, Fridays and Saturdays between 01-06-2009 and 02-07-2019
Known Errors and Limitations
The formula returns #VALUE! error when you try really long durations (like trying to find all the workingdays between now and a century later)
Another thing is, you cannot feed a custom holiday list to this formula. But that is very easy to add on, so I didn’t bother.
So go ahead and give it a try
Download the NetWorkingDays() UDF Excel Add-in
and tell me what you think…
On dates and times in Excel: Date & Time Formulas | 10 Tips on Using Dates & Times in Excel
6 Responses to “Make VBA String Comparisons Case In-sensitive [Quick Tip]”
Another way to test if Target.Value equal a string constant without regard to letter casing is to use the StrCmp function...
If StrComp("yes", Target.Value, vbTextCompare) = 0 Then
' Do something
End If
That's a cool way to compare. i just converted my values to strings and used the above code to compare. worked nicely
Thanks!
In case that option just needs to be used for a single comparison, you could use
If InStr(1, "yes", Target.Value, vbTextCompare) Then
'do something
End If
as well.
Nice tip, thanks! I never even thought to think there might be an easier way.
Regarding Chronology of VB in general, the Option Compare pragma appears at the very beginning of VB, way before classes and objects arrive (with VB6 - around 2000).
Today StrComp() and InStr() function offers a more local way to compare, fully object, thus more consistent with object programming (even if VB is still interpreted).
My only question here is : "what if you want to binary compare locally with re-entering functions or concurrency (with events) ?". This will lead to a real nightmare and probably a big nasty mess to debug.
By the way, congrats for you Millions/month visits 🙂
This is nice article.
I used these examples to help my understanding. Even Instr is similar to Find but it can be case sensitive and also case insensitive.
Hope the examples below help.
Public Sub CaseSensitive2()
If InStr(1, "Look in this string", "look", vbBinaryCompare) = 0 Then
MsgBox "woops, no match"
Else
MsgBox "at least one match"
End If
End Sub
Public Sub CaseSensitive()
If InStr("Look in this string", "look") = 0 Then
MsgBox "woops, no match"
Else
MsgBox "at least one match"
End If
End Sub
Public Sub NotCaseSensitive()
'doing alot of case insensitive searching and whatnot, you can put Option Compare Text
If InStr(1, "Look in this string", "look", vbTextCompare) = 0 Then
MsgBox "woops, no match"
Else
MsgBox "at least one match"
End If
End Sub