Van Gysel asked in a recent post at Chandoo.org for a way to calculate the costs of running a plantation. The twist is that the costs vary by year, and based on the age of the trees.
The following is a slightly simplified version of the solution I offered:
=SUM(IFERROR(LOOKUP(“Year”&MMULT(N($B$3:B$7>0),TRANSPOSE(COLUMN($B$3:B$7)^0)), $B$11:$I$11, $B12:$I12),0)*B$3:B$7) Ctrl+Shift+Enter
Today I am going to try and explain how the formula works.
As always at Formula Forensics, you can follow along with a sample file: Download Here
The Problem
In a plantation, the costs for planting and maintaining trees vary based on the age of the trees and by year. The table below shows the acres of trees planted per year and the yield and costs per year that vary based on the age of the trees.
Let us look at the calculations needed for each year.
Year 2013
- 300 acres of trees were planted in 2013. Calculations for 2013 are as follows. (Only Yield calculation is shown, but the process is similar for Nursery costs, Fertilizers, etc.)
- The trees do not yield any fruits in the first year. As such, Yield for year1=300*0=0
That was easy!
Year 2014
- 700 additional acres of trees will be planted in 2014. Calculations for 2014 are as follows. (Again, only Yield calculation is shown, but others are calculated similarly.)
- 300 acres of trees are 2 years old. 700 acres are 1 year old.
- The 300 acres from 2013 now yield fruit since it is year2. However, the new trees (700 acres) do not yield any fruits yet. So total yield for 2014=300*Year2Yield+700*Year1Yield=300*5+700*0
Year 2015
- 1000 additional acres are to be planted in 2015. Calculations for 2015 are as follows:
- 300 acres are from 2013 (3 years old); 700 acres are from 2014 (2 years old); 1000 acres are from 2015 (1 year old).
- Yield for 2015=300*Year3Yield + 700*Year2Yield + 1000*Year1Yield = 300*10 + 700*5 + 1000*0
Year 2016
- 1000 additional acres are to be planted in 2016. Calculations for 2016 are as follows:
- Yield for 2016=300*15+700*10+1000*5+1000*0
How do we simulate the above calculation in an Excel formula?
A Solution
Let us first look at how we performed the calculations above manually, using the 2016 Yield as an example.
- We took each acreage value in 2016, and determined its age by counting how many years it has been since that acreage was planted. You might have observed that the age can be counted by the number of times a value has been repeated up to that point. (In other words, if I planted 300 acres in 2013, I should see that same amount in 2014, 2015 and 2016.) As such, 300 acres is repeated 4 times. 700 acres is repeated 3 times. 1000 acres is repeated 2 times. And the latest planting of 1000 acres exists only once.
- Once we determine the age for a given acreage, we looked up the yield for that age in the second table
- We then multiplied the acreage with the corresponding yield value.
Calculation #1 can be expressed as follows:
- Age for acreage 1 (first planted in 2013)=count of B3:E3 where value is greater than zero. i.e. COUNTIF(B3:E3,”>0”)
- Age for acreage 2 (planted in 2014)=count of B4:E4 where value is greater than zero. i.e. COUNTIF(B4:E4,”>0”)
- Age for acreage 3 (planted in 2015)=count of B5:E5 where value is greater than zero. i.e. COUNTIF(B5:E5,”>0”)
- Age for acreage 4 (planted in 2016)=count of B6:E6 where value is greater than zero. i.e. COUNTIF(B6:E6,”>0”)
- Age for acreage 5 is zero since nothing has been planted for 2017 yet in 2016
The above approach would work if we were calculating the age one row at a time. However, that can become tedious really fast. We need to perform the calculation for the full range (B3:E7) together, but return the counts for each row individually.
Excel’s MMULT function comes to the rescue!
MMULT (which stands for Matrix Multiply) multiplies two matrices and returns a third matrix based on rules for matrix multiplication. I am planning to devote a whole article to explain the MMULT function. As such, for this article, we will summarize the utility of the function as “take a 2-dimensional array, add each column’s value for each row, and return a 1-column array”.
MMULT requires that its arguments be numeric.
So to obtain the counts for the year 2016, we can use the following:
MMULT(N($B$3:E$7>0),TRANSPOSE(COLUMN($B$3:E$7)^0))
As you can see from the picture below, MMULT’s results are the addition of each column for each row.
In the above formula, you may have noticed that the range uses absolute and relative referencing (signified by the $ sign or lack thereof). This is to ensure that the range grows or shrinks as needed. The upper left address is held constant ($B$3). However, the lower right address for the range has columns that vary but row that is fixed on row #7. This ensures that the formula would work if we copy to the left, right, etc. in the final results.
Now that we have the age for each acreage value, we can look up the corresponding yield value using (what else?) LOOKUP function.
But before we can use LOOKUP, we will need to convert the numeric values returned from MMULT into the strings Year1, Year2, etc. found in the Costs table. Of course, you know how to do that… concatenate the string “Year” to the result from MMULT
“Year”&MMULT(N($B$3:E$7>0),TRANSPOSE(COLUMN($B$3:E$7)^0))
For the 2016 example, we get {“Year4″;”Year3″;”Year2″;”Year1″;”Year0”}
We can now use LOOKUP as follows:
LOOKUP(“Year”&MMULT(N($B$3:E$7>0),TRANSPOSE(COLUMN($B$3:E$7)^0)), $B$11:$I$11, $B12:$I12)
You may recall that LOOKUP looks up a value in the array indicated by the second argument, and returns the corresponding value from the third array argument. In this case, instead of looking up a single value, we look up an array of values (supplied in the first argument) to the function.
The above formula translates to the following:
LOOKUP({“Year4″;”Year3″;”Year2″;”Year1″;”Year0”}, {“Year1″,”Year2″,”Year3″,”Year4″,”Year5″,”Year6″,”Year7″,”Year8”}, {0,5,10,15,20,25,30,35})
The result from LOOKUP is {15;10;5;0;#N/A}
(The last value is #N/A because there is no acreage value for 2017 yet (as of 2016 column). The concatenation resulted in Year0 which does not exist in the “Age of The Trees” range (B11:I11) above.)
By using IFERROR(LOOKUP(…),0) we get {15;10;5;0;0}
We can now multiply the above result with the acreage values for 2016 to get {4500;7000;5000;0;0}
Finally, we SUM the values to get 16500
Putting it all together, we get the following formula (shown for Production for year 2016)
=SUM(IFERROR(LOOKUP(“Year”&MMULT(N($B$3:E$7>0),TRANSPOSE(COLUMN($B$3:E$7)^0)), $B$11:$I$11, $B12:$I12),0)*E$3:E$7)
One of the benefits of the above formula is that you can copy the same formula to calculate values for additional years, as well as other plantation costs.
Download
You can download a copy of the above file and follow along: Download sample file.
Let me know (using the comments below) what you think of the above approach and solution, as well as any other approaches you have utilized to solve a similar problem. In the meantime, I wish you continued Excellence!
-Sajan.
Other Posts in this Series
The Formula Forensics Series contains a wealth of useful solutions and information.
Visit the Formula Forensics Home Page to read other articles in this series.
38 Responses to “Time to showoff your VBA skills – Help me fix ActiveSheet.Pictures.Insert snafu”
I tried your code with 2003, it works.
But, I know Addpicture does not take URLs anymore with 2007 onwards, perhaps its the same with picture.insert as well.
http://support.microsoft.com/kb/928983/en-us
The above link gives the solution as "picture fill in a shape such as a rectangle".
Tried to recreate this, but it worked fine for me. I just took the image of the error you showed in the post. Is there more info that can narrow this down a bit?
Don't know if this helps?
http://www.theserverside.com/discussions/thread.tss?thread_id=47101
Hi
Not sure if this is what you're after, but I just tried this
Sub Macro1()
ActiveSheet.Pictures.Insert("http://www.google.co.uk/intl/en_uk/images/logo.gif").Select
End Sub
Tied a button to it on the sheet and it seems to work; hope this helps a little
Ian
@All.. the issue is in Excel 2007. In 2003 ActiveSheet.Pictures.Insert seems to work fine. Unfortunately, I have design this in Excel 2007.. that is why I posted it here..
v2
Sub Macro1()
Set n = ActiveSheet.Pictures.Insert("http://www.google.co.uk/intl/en_uk/images/logo.gif")
With Range("c12")
t = .Top
l = .Left
End With
With n
.Top = t
.Left = l
End With
End Sub
Ian
That didn't come out very well. This positions at c12, so can change easily:
Sub Macro1()
Set n = ActiveSheet.Pictures.Insert("http://www.google.co.uk/intl/en_uk/images/logo.gif")
With Range("c12")
t = .Top
l = .Left
End With
With n
.Top = t
.Left = l
End With
End Sub
Works OK in 2007
Ian
The above codes work fines to my EXCEL 2007. Thanks.
Chandoo:
Try 'ActiveSheet.Pictures.Insert'
With ActiveSheet.Pictures.Insert("C:\Example.png")
.Left = ActiveSheet.Range("A1").Left
.Top = ActiveSheet.Range("A1").Top
End With
activesheet.pictures.insert "C:\Documents and Settings\Jon Peltier\Desktop\2007 stuff\insert_charts_2007.png"
Works for me in 2003 SP3 and in 2007 SP2.
Check the URL, and make sure you have internet connectivity.
What also works, and is newer (pictures.insert was supposedly deprecated in '97):
activesheet.shapes.addpicture "C:\Documents and Settings\Jon Peltier\Desktop\2007 stuff\insert_charts_2007.png", false, true, 200,200,100,100
Unfortunately you must specify dimensions (the last four arguments) and you don't necessarily know them. But the picture size is still related back to the original picture size, so you could use scaleheight and scalewidth to fix this.
Chandoo: I just re-read your post.
The code I posted works for me. However, I'm using a local picture. If you try to add a picture from the web, this won't work.
I remember solving this problem before by adding a rectangle shape first, then using the Shapes.AddPicture method to get a picture from the web.
I'll find that code and post it here.
Some more updates... The code "ActiveSheet.Pictures.Insert (path)" works fine in Excel 2007 at home. Strange it failed miserably on my work laptop. Do you think this has got something to do with SP2 of MS Office 2007 or something like that?
@Ian, Jon: Thanks for the code snippets. I guess I will use my home installation of excel to do this.
Chandoo:
Try this on your work laptop:
Sub test()
ActiveSheet.Shapes.AddShape msoShapeRectangle, 50, 50, 100, 200
ActiveSheet.Shapes(1).Fill.UserPicture _
"http://www.datapigtechnologies.com/images/dpwithPig6.png"
End Sub
FYI:
http://support.microsoft.com/kb/928983/en-us
I didn't mean to post code with a local file, because both approaches worked with an internet image as well. This is in Excel 2007 SP2.
activesheet.pictures.insert "http://peltiertech.com/images/2009-07/col_area_noblanks.png"
Jon: Looks like I have SP1 on my client machine! I wasn't paying attention.
Just checked my home computer where I have SP2, and you're right...looks like they fixed it.
I didn't even bother testing in SP1, though I could if anyone cares enough.
I'm afraid I don't have a solution, but I find it remarkable that after attaining a certain status in the Excel world, Chandoo does not need to post on an Excel discussion forum to get help for an Excel problem. Instead, he posts on his blog and all the gurus come rushing to his help.
Isn't Web 2.0 great?
Teylyn - I saw Chandoo's tweet first, and followed the link back to his blog.
@Mike.. thank you. I have seen the fill rectangle solution before posting the query here. For that matter, I have also tried the solution of embedding a browser control on a spreadsheet. both of these seemed a bit extreme. That is why I have asked it here.
But I guess I will end up using it if I had to build this in work laptop.
@Teylyn: I have thought of posting this in a forum. (Unfortunately I have not been to any excel group in the last 5 years. Last time I was active was when I built a jave based excel sheet construction solution using POI.HSSF classes of Apache... ) After searching for a few hours, I found several forum posts where others had same problem and the solution recommended (using .left and .top parameters) is not working for me. Incidentally most of these solutions are from a certain Jon Peltier 😛
I thought may be the problem is interesting for fellow blog readers. So I posted it here.
Hi,
Adapting the code in the question,
[code]
Sub InsPicture()
pPath = "http://chandoo.org/images/pointy-haired-dilbert-excel-charts-tips.png"
With ActiveSheet.Pictures.Insert(pPath)
.Left = Range("a1").Left
.Top = Range("a1").Top
End With
End Sub
[/code]
Seems to work fine
Looks like it was a problem in 2007 up to SP1, which was corrected in SP2.
@Jon.. seems like the case. I just checked the version at work laptop. it is 12.0.6331.5000 (SP1).
Thank you so much every one. I really appreciate your time and suggestions in solving this.
Glad to help. I couldn't understand why something so straightforward wasn't working.
Hi All
Is there a way of inserting a motion clip eg animated gif or swf or flv?
Thks
You can insert animated GIFs by inserting them in a browser control through VBA. For other types of movies, I can guess you can insert them as clip art.
I WANT THE INSERT PICTURE BY USING COADING
so currently i was struggling same as you, chandoo, with the insert picture method in excel 2007/10 from an url and came along your thread here.
so i re-designed the code on the addshape method as mike was suggesting it and all of the sudden it works just fine.
thanks alot to you guys, you were a great help
a big salut from switzerland
Hi guys,
I need help copying and pasting an image with the path in a cell.
I leave the code.
And thank you very much!
Sub Copiarimg()
Dim pic As Picture
With ActiveSheet
Set pic = .Pictures.Insert(Range("f2").Value)
With .Range("e9:g22")
pic.Top = .Top
pic.Left = .Left
pic.Width = .Width
pic.Height = .Height
End With
End Sub
I've played around with the approaches in these comments, and the code below is what I've come up with. The ImagePath can be a local file or a URL. As Jon mentioned above, the trick is to set an arbitrary value for the width and height, then call the ScaleWidth and ScaleHeight methods afterward to reset the picture to its original size. Once the LockAspectRatio property is set, you can change the picture width and the height will automatically scale (or vice-versa).
Sub AddPictureToRange(TopLeftCellAddress As String, ImagePath As String)
Dim pic As Shape
Dim l As Single, t As Single
Dim temp As Single
l = Me.Range(TopLeftCellAddress).Left
t = Me.Range(TopLeftCellAddress).Top
temp = 10# ' arbitrary value
Set pic = Me.Shapes.AddPicture(ImagePath, msoFalse, msoTrue, l, t, temp, temp)
pic.ScaleHeight 1#, msoTrue
pic.ScaleWidth 1#, msoTrue
pic.LockAspectRatio = msoTrue
End Sub
I need some help with inserting pictures. I have an excel file with a column of item numbers next to this row I want to insert a picture of this item. The pictures are coded with the item number so I tried to insert it with one of the codes above:
Sub InsPicture()
pPath = "http://img.bricklink.com/P/80/55236.gif"
With ActiveSheet.Pictures.Insert(pPath)
End With
End Sub
That worked but I need to do that for every row separtly.
So I tried in the code
pPath = "http://img.bricklink.com/P/80/"&Text(a1;"#")&".gif"
But that gives errors.
Anybody ideas?
Hi Nicholas, I used your solution in a related problem in Excel 2003 and it worked flawlessly..thank you!
Hi Mike Alexander,
Your solution with some changes was helpful in my problem in XL 2007, thanks.
Hi,
thanks all. In addition, I had a problem with multiple pictures inserting (every new picture replaced the prior one). I've changed it a bit, may be helpful..
Sub test()
ActiveSheet.Shapes.AddShape msoShapeRectangle, 50 , 50, 100, 200
ActiveSheet.Shapes(1).Fill.UserPicture _
"http://www.datapigtechnologies.com/images/dpwithPig6.png"
ActiveSheet.Shapes(1).Copy
ActiveSheet.Paste
End Sub
Try this instead:
Sub test()
ActiveSheet.Shapes.AddShape msoShapeRectangle, 50 , 50, 100, 200
ActiveSheet.Shapes(ActiveSheet.Shapes.Count).Fill.UserPicture _
"http://www.datapigtechnologies.com/images/dpwithPig6.png"
End Sub
Thanks to everyone, this thread has been very helpful. However, image inserting still doesn't work quite as expect for me.
While I can get a picture inserted into an Excel 2010 worksheet using either:
1) ActiveSheet.Shapes(ActiveSheet.Shapes.Count).Fill.UserPicture...
2) ActiveSheet.Pictures.Insert(pPath), and
3) Shapes.AddPicture...
unfortunately the images all insert with a display size determined not by the actual pixel dimensions of the image but by the dpi resolution.
So for example, if I insert two copies of the exact same 600x600 pixel image, one with a 300dpi resolution and the other with 72dpi, they display at vastly different sizes on screen.
While this might be intended behaviour for Excel in order to maintain a WSYWIG printing layout, I actually need a way to insert the image based on the the actual pixel dimesnsions and ignoring the dpi resolution.
Any help appreciated.
Thanks
Kez
Not doing an intentional bump, but realised I posted in rely to one of the repsonses here instead of to the main thread, so reposting.
=====
Thanks to everyone, this thread has been very helpful. However, image inserting still doesn’t work quite as expected for me.
While I can get a picture inserted into an Excel 2010 worksheet using any of the below methods:
1) ActiveSheet.Shapes(ActiveSheet.Shapes.Count).Fill.UserPicture....
2) ActiveSheet.Pictures.Insert(pPath), and
3) Shapes.AddPicture....
unfortunately the images all insert with a display size determined not by the actual pixel dimensions of the image but by the dpi resolution.
So for example, if I insert two copies of the exact same 600×600 pixel image, one with a 300dpi resolution and the other with 72dpi, they display at vastly different sizes in Excel on screen.
While this might be intended behaviour for Excel in order to maintain a WYSIWYG printing layout, I actually need a way to insert the images based on the the actual pixel dimesnsions and ignoring the dpi resolution.
Any help appreciated.
Thanks
Kez
Well, answered my own question 🙂
For those who might be interested, you can use this function:
Public Function GetPicDims(strFilePath As String, strFileName As String) As String
GetPicDims = CreateObject("Shell.Application").Namespace((strFilePath)). _
ParseName(strFileName).ExtendedProperty("Dimensions")
End Function
to get the dimensions of the image you want to insert. Then you can parse the return string and use the width and height values to add a rectangle shape of the appropraite size, like:
ActiveSheet.Shapes.AddShape msoShapeRectangle 50, 50, iWidth, iHeight
which you then fill with the picture:
ActiveSheet.Shapes(ActiveSheet.Shapes.Count).Fill.UserPicture "c:\temp\test.jpg"
This way the picture gets inserted using the pixel dimensions and the (print) resolution gets ignored.
If desired, the GetPicDims function can be made more generic to get other ExtendedProperties.
Regards
Kez