Quickly Fill Blank Cells in a Table [Reader Tip]

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This post is authored by Martin, one of our readers.

Situation:

Sometimes I encounter data in my tables with blank cells where there is a repeated value from the cell directly above. See below:

Quickly Fill Blank Cells in a Table - Excel Tip

This can be annoying when it comes to interpreting the data and when sorting columns.

Solution:

Here’s the solution I use.

1. Select the whole table. I favor the shortcut Ctrl A to do this. Make sure you perform this shortcut from within the table though as otherwise the entire worksheet with be selected. This gives us Figure 2:

Select all the cells in a table using CTRL+A

2. Next we will open the Go To dialog box. This is a very useful dialog for selecting certain types of cells, for example cells containing formulas, constant values, visible cells and so on. F5 or Ctrl G both work as keyboard shortcuts.

3. Click the Special button (see Figure 3)

Use Goto Dialog box to select the blank cells

4. In the next screen select Blanks.

Select all blank cells

5. Click OK and notice that all blank cells are now highlighted in the table (Figure 5). Notice too, the position of the active cell. This is the one un-shaded cell in this selection. In this example it is cell D3. If the table were fully complete this cell would show the same value as the cell above it – cell D2 – the word Office.

All the blank cells are now selected

6. Next we will use the fact that cell references in Excel by default behave in a relative manner. That means when you copy a formula to another cell, the cell reference in the formula change relative to the location in the worksheet it has been moved to unless they have been made absolute.

7. Without clicking any of the cells in the data, simply enter the following simple formula:

=D2

If you are following along here with a different table, then you will substitute the cell reference of the cell directly above your active cell. (Figure 6)

Use a formula to copy the value from above

8. Next the important part. We need to copy this simple formula to all the other blank cells which could number in the hundreds or thousands or greater still. How do we do it?

Simply by using one of the best keyboard shortcuts I know in Excel: Ctrl & Enter.

This shortcut when used in a single cell will enter the value inputted into the cell and keep that cell active, instead of performing a carriage return to the next row.

But, when used over a range of cells, Ctrl & Enter together will copy the value of the active cell into all cells in the selection.

In this case, we are not going to copy the value of D2 into all blank cells, but the relative cell that appears over each blank cell. In cell D3’s case this was D2. In A3’s case for example it is A2 and so on.

After CTRL Entering the formula the worksheet now looks like:

After typing the formula, this is how the table looks like

9. There is one last important step. These pasted valued are, as we have seen, relative formulas. If I were to change the sort order in one of the columns, for example to identify which Cost in column E is the highest, my table would be completed distorted as the formulas in the changing rows are all retrieving the value in the cell above. See Figure 8.

The formulas return incorrect values if the list is sorted differently

I’ll Undo my flawed Sort by clicking Ctrl Z.

The final step therefore is to change these formulas into constants so that this type of problem can be avoided.

To do this, select the table, (or if the formula cells remain highlighted, you won’t need to select the table at all).

Now copy your selection with Ctrl C.

Next, perform a Paste Special / Values to replace the formulas with their constant equivalents – Figure 9.

Change formulas to values using Paste Special

And that’s it!

Thank you Martin

Many thanks to Martin for sharing this simple yet very beautiful trick with all of us. If you enjoyed this article, say thanks to Martin.

How do you deal with Blank Cells

Barking dogs, bad bosses and blank cells are everywhere. I am eager to know how you deal with them. Please share your tips & techniques with us using comments.

More on Blank Cells and other Unclean Data

If you constantly deal with blank cells or other types of unclean data, read these articles to learn few more tricks.

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14 Responses to “How many ‘Friday the 13th’s are in this year? [Formula fun + challenge]”

  1. in C3=2016
    in C4=3
    in C5=1 (the first next year with three Friday the 13ths)

    =SMALL(IF(MMULT(--(MOD(DATE(C3+ROW(1:1000),COLUMN(A:L),13),7)=6),ROW(1:12)^0)=C4,C3+ROW(1:1000)),C5)

    formula check in the next 1000 years

  2. Brian says:

    This will generate a table of counts of Friday the 13th's by year. If I didn't screw it up the next year with three is 2026.

    I created a simple parameter table with a start date and end date that I wanted to evaluate. That calculates the number of days and generates a list of those days. Then filter and group. The generation of the list in power query (i.e. without populating a date table in excel) is pretty cool, otherwise this isn't really doing anything than creating a big date and filtering/counting.

    let
    Source = List.Dates(StartDateAsDate, Days2, #duration(1,0,0,0)),
    ConvertDateListToTable = Table.FromList(Source, Splitter.SplitByNothing(), null, null, ExtraValues.Error),
    AddDayOfMonthColumn = Table.AddColumn(ConvertDateListToTable, "DayOfMonth", each Date.Day([Column1])),
    AddYearColumn = Table.AddColumn(AddDayOfMonthColumn, "Year", each Date.Year([Column1])),
    AddDayOfWeekColumn = Table.AddColumn(AddYearColumn, "Day of Week", each Date.DayOfWeek([Column1])),
    FilterFriday13 = Table.SelectRows(AddDayOfWeekColumn, each ([DayOfMonth] = 13) and ([Day of Week] = 5)),
    Friday13thsByYear = Table.Group(FilterFriday13, {"Year"}, {{"Number of Friday the 13ths!", each Table.RowCount(_), type number}})
    in
    Friday13thsByYear

    • Brian says:

      With the parameters replaced by values should you want to play along at home. This runs for 20 years starting on 1/1/2016.

      let
      Source = List.Dates(#date(2016,1,1), 7300, #duration(1,0,0,0)),
      ConvertDateListToTable = Table.FromList(Source, Splitter.SplitByNothing(), null, null, ExtraValues.Error),
      AddDayOfMonthColumn = Table.AddColumn(ConvertDateListToTable, "DayOfMonth", each Date.Day([Column1])),
      AddYearColumn = Table.AddColumn(AddDayOfMonthColumn, "Year", each Date.Year([Column1])),
      AddDayOfWeekColumn = Table.AddColumn(AddYearColumn, "Day of Week", each Date.DayOfWeek([Column1])),
      FilterFriday13 = Table.SelectRows(AddDayOfWeekColumn, each ([DayOfMonth] = 13) and ([Day of Week] = 5)),
      Friday13thsByYear = Table.Group(FilterFriday13, {"Year"}, {{"Number of Friday the 13ths!", each Table.RowCount(_), type number}})
      in
      Friday13thsByYear

  3. Alex Groberman says:

    =MATCH(3,MMULT(N(WEEKDAY(DATE(C3+ROW(1:100)-1,COLUMN(A:L),13))=6),1^ROW(1:12)),)+C3-1

    • David N says:

      It should be pointed out that Alex's solution, unlike some others, has the additional advantage of being non-array. My solution was nearly identical but with -- and SIGN instead of N and 1^.

      =C3-1+MATCH(3,MMULT(--(WEEKDAY(DATE(C3-1+ROW(1:25),COLUMN(A:L),13))=6),SIGN(ROW(1:12))),0)

  4. SunnyKow says:

    Sub Friday13()

    Dim StartDate As Date
    Dim EndDate As Date
    Dim x As Long
    Dim r As Long

    Range("C7:C12").ClearContents
    StartDate = CDate("01/01/" & Range("C3"))
    EndDate = CDate("31/12/" & Range("C3"))
    r = 7
    For x = StartDate To EndDate
    If Day(x) = 13 And Weekday(x, vbMonday) = 5 Then
    Cells(r, 3) = Month(x)
    r = r + 1
    End If
    Next
    End Sub

    • SunnyKow says:

      Calculate next year with 3 Friday 13th. Good for 100 years different from year entered in cell C3

      Sub ThreeFriday13()

      Dim StartDate As Date
      Dim EndDate As Date
      Dim x As Long
      Dim WhatYear As Integer
      Dim Counter As Integer

      Range("E7").ClearContents
      StartDate = CDate("01/01/" & Range("C3") + 1)
      EndDate = CDate("31/12/" & Range("C3") + 100)
      Counter = 0

      For x = StartDate To EndDate
      If WhatYear Year(x) Then
      WhatYear = Year(x)
      'Different year so reset counter
      Counter = 0
      End If
      If Day(x) = 13 And Weekday(x, vbMonday) = 5 Then
      Counter = Counter + 1
      If Counter = 3 Then
      WhatYear = Year(x)
      Exit For
      End If
      End If
      Next
      Range("E7") = WhatYear

      End Sub

      • SunnyKow says:

        *RE-POST as not equal did not show earliuer
        Calculate next year with 3 Friday 13th. Good for 100 years different from year entered in cell C3

        Sub ThreeFriday13()

        Dim StartDate As Date
        Dim EndDate As Date
        Dim x As Long
        Dim WhatYear As Integer
        Dim Counter As Integer

        Range("E7").ClearContents
        StartDate = CDate("01/01/" & Range("C3") + 1)
        EndDate = CDate("31/12/" & Range("C3") + 100)
        Counter = 0

        For x = StartDate To EndDate
        If WhatYear NE Year(x) Then
        WhatYear = Year(x)
        'Different year so reset counter
        Counter = 0
        End If
        If Day(x) = 13 And Weekday(x, vbMonday) = 5 Then
        Counter = Counter + 1
        If Counter = 3 Then
        WhatYear = Year(x)
        Exit For
        End If
        End If
        Next
        Range("E7") = WhatYear

        End Sub

  5. Devesh says:

    I've a doubt with using array formula here.
    In sample workbook, I tried to replicate the formula again.
    =IFERROR(SMALL(IF(WEEKDAY(DATE($C$3,ROW($A$1:$A$12),13))=6,ROW($A$1:$A$12)),$B7),"")
    For this I selected C7 to C12, and typed the same formula and pressed ctrl+alt+Enter. But in all cells it is taking $B7 (and not $B7, $B8, $B9.... etc)
    and since it is array formula I can't edit individual cell.
    Please guide.
    Thanks

  6. Pablo says:

    Hi Chandoo,
    Cool stuff. You need to clarify that the answer of 5 represents the 1st month in the year that has a Friday the 13th, and not the number of Fridays the 13th in the year. Subtle, but important difference.
    Thanks,
    Pablo

  7. Micah Dail says:

    I like the MMULT() function far more, but here's how I would have tackled it. It uses an EDATE() base and MODE() over 100 years. I'm assuming that 100 years is enough time to catch the next year with 3 friday 13th's. Array entered, of course.

    {=MODE(IFERROR(YEAR(IF((WEEKDAY(EDATE(DATE(C3, 1, 13), ROW(INDIRECT("1:1200"))))=6), EDATE(DATE(C3, 1, 13), ROW(INDIRECT("1:1200"))), "")), ""))}

  8. Jason Morin says:

    Finding all the Friday the 13ths in a Year:

    =SUMPRODUCT((DAY(ROW(INDIRECT(DATE(C3,1,1)&":"&DATE(C3,12,31))))=13)*(TEXT(ROW(INDIRECT(DATE(C3,1,1)&":"&DATE(C3,12,31))),"ddd")="Fri"))

  9. jmdias says:

    {=sum(if(day.of.week(DATe($YEAR;{1;2;3;4;5;6;7;8;9;10;11;12};13);1)=6;1;0))}
    just list the years

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