In this post we will learn how to use the Advanced Filter option using VBA to allow us to filter our data on a separate sheet. This has been requested by a lot of our readers and here is how we will use them.
What we need to get this done.
1. Some data that we need filtering on.
2. Define what options we need as drop down lists
3. A cup of coffee
In the sample data, I have defined 4 options to be available as drop down list; this has been done by creating a new sheet called as “Master”. I then copied the existing columns data into this sheet and used the Remove Duplicates feature to get the unique list of items that was required for the drop downs.
The named ranges were created using the INDEX function as shown below
| Named Range | Formula |
| prd | =Master!$A$2:INDEX(Master!$A:$A,COUNTA(Master!$A:$A)) |
| rgn | =Master!$B$2:INDEX(Master!$B:$B,COUNTA(Master!$B:$B)) |
| cust | =Master!$C$2:INDEX(Master!$C:$C,COUNTA(Master!$C:$C)) |
| agnt | =Master!$D$2:INDEX(Master!$D:$D,COUNTA(Master!$D:$D)) |
Now we need to setup the sheet where we need the filtered data to be displayed. Headings were put in cells B5 to B8 and the drop down (using the Data Validation—List) feature was put in cells C5 to C8. Now we need to create or criteria fields in the RawData sheet, this is a requirement and cannot be any place else. When you use the Advanced Filter dialog box and try to place the output onto another sheet Excel will display a message saying “You can only copy data to the Active Sheet”. We will overcome this limit by using VBA and telling Excel where to put the filtered data. I used the cells M1 to P1 to define the headings and cells M2 to P2 to get the actual options from the “Filter Sheet”
| Cells | Formula |
| M2 | =Filter!C5 |
| N2 | =Filter!C6 |
| O2 | =Filter!C7 |
| P2 | =Filter!C8 |
Macro to run advanced filter and extract data
Sub FilterData()
Sheets("Filter").Select
Range("B10").Select
Range(Selection, Selection.End(xlToRight)).Select
Range(Selection, Selection.End(xlDown)).Select
Selection.Clear
Sheets(“RawData”).Range(“Table1[#All]”).AdvancedFilter Action:=xlFilterCopy, CriteriaRange:= _
Sheets(“RawData”).Range(“M1:P2”), CopyToRange:=Sheets(“Filter”).Range(“B10”), Unique:=True
Columns.AutoFit
Range(“B10”).Select
End Sub
First we ensure the current filtered data (in any) is cleared out before we run the code again and then we get the new filtered data from cell B10 onwards. Now let’s understand the actual code that filters our data here.
Sheets("RawData").Range("Table1[#All]").AdvancedFilter
Action:=xlFilterCopy,
CriteriaRange:=Sheets("RawData").Range("M1:P2"),
CopyToRange:=Sheets("Filter").Range("B10"),
Unique:=True
We converted our raw data into an excel table (Structured Reference Structured Reference), by doing this we no longer need to know how many rows our data actually goes down to, the “Table1[#All]” takes care of that for us.
We also need to specify that our data is in another sheet and we are trying to run Advanced Filter on that data range, this is done using the first line ” Sheets(“RawData”).Range(“Table1[#All]”).AdvancedFilter “.
Next we specify the action that we need which is Copy in our case, the other option is “xlFilterInPlace” which would filter right on our data itself.
Then we have specified the Criteria Range (which needs to be on the same sheet where the data is).
And finally we have specified where the output has to be sent to by using : “CopyToRange:=Sheets(“Filter”).Range(“B10″)”
We have also made sure that only Unique records are returned to us by turning Unique:=True.
Download Advanced Filter Demo File
Click here to download the demo file & use it to understand this technique.
Do you use Advanced filters to extract sub-sets of data?
Advanced filters are very powerful and very simple to setup. I use them often to quickly extract what I want.
What about you? Do you use them often? Please share your experiences, techniques & ideas using comments.
Learn more about extracting / consolidating data using VBA
Data extraction and consolidation are one of the most common activities done by reporting professionals & analysts. No wonder we speak about these areas a lot here too. Please check out these pages to learn more:
- Split an excel file in to many using Advanced Filters & VBA [with video]
- Move data from one sheet to many using VBA
- Split text on new line using VBA
- Consolidate data from multiple files in to one using VBA Macros
Want to lean more? Consider joining our VBA Classes
If you would like to learn more about VBA programming, Excel automation, creation of user forms, manipulating data in Access thru Excel etc., consider joining our online VBA Classes. This step-by-step program helps you become awesome in VBA.
14 Responses to “How many ‘Friday the 13th’s are in this year? [Formula fun + challenge]”
in C3=2016
in C4=3
in C5=1 (the first next year with three Friday the 13ths)
=SMALL(IF(MMULT(--(MOD(DATE(C3+ROW(1:1000),COLUMN(A:L),13),7)=6),ROW(1:12)^0)=C4,C3+ROW(1:1000)),C5)
formula check in the next 1000 years
This will generate a table of counts of Friday the 13th's by year. If I didn't screw it up the next year with three is 2026.
I created a simple parameter table with a start date and end date that I wanted to evaluate. That calculates the number of days and generates a list of those days. Then filter and group. The generation of the list in power query (i.e. without populating a date table in excel) is pretty cool, otherwise this isn't really doing anything than creating a big date and filtering/counting.
let
Source = List.Dates(StartDateAsDate, Days2, #duration(1,0,0,0)),
ConvertDateListToTable = Table.FromList(Source, Splitter.SplitByNothing(), null, null, ExtraValues.Error),
AddDayOfMonthColumn = Table.AddColumn(ConvertDateListToTable, "DayOfMonth", each Date.Day([Column1])),
AddYearColumn = Table.AddColumn(AddDayOfMonthColumn, "Year", each Date.Year([Column1])),
AddDayOfWeekColumn = Table.AddColumn(AddYearColumn, "Day of Week", each Date.DayOfWeek([Column1])),
FilterFriday13 = Table.SelectRows(AddDayOfWeekColumn, each ([DayOfMonth] = 13) and ([Day of Week] = 5)),
Friday13thsByYear = Table.Group(FilterFriday13, {"Year"}, {{"Number of Friday the 13ths!", each Table.RowCount(_), type number}})
in
Friday13thsByYear
With the parameters replaced by values should you want to play along at home. This runs for 20 years starting on 1/1/2016.
let
Source = List.Dates(#date(2016,1,1), 7300, #duration(1,0,0,0)),
ConvertDateListToTable = Table.FromList(Source, Splitter.SplitByNothing(), null, null, ExtraValues.Error),
AddDayOfMonthColumn = Table.AddColumn(ConvertDateListToTable, "DayOfMonth", each Date.Day([Column1])),
AddYearColumn = Table.AddColumn(AddDayOfMonthColumn, "Year", each Date.Year([Column1])),
AddDayOfWeekColumn = Table.AddColumn(AddYearColumn, "Day of Week", each Date.DayOfWeek([Column1])),
FilterFriday13 = Table.SelectRows(AddDayOfWeekColumn, each ([DayOfMonth] = 13) and ([Day of Week] = 5)),
Friday13thsByYear = Table.Group(FilterFriday13, {"Year"}, {{"Number of Friday the 13ths!", each Table.RowCount(_), type number}})
in
Friday13thsByYear
=MATCH(3,MMULT(N(WEEKDAY(DATE(C3+ROW(1:100)-1,COLUMN(A:L),13))=6),1^ROW(1:12)),)+C3-1
It should be pointed out that Alex's solution, unlike some others, has the additional advantage of being non-array. My solution was nearly identical but with -- and SIGN instead of N and 1^.
=C3-1+MATCH(3,MMULT(--(WEEKDAY(DATE(C3-1+ROW(1:25),COLUMN(A:L),13))=6),SIGN(ROW(1:12))),0)
Sub Friday13()
Dim StartDate As Date
Dim EndDate As Date
Dim x As Long
Dim r As Long
Range("C7:C12").ClearContents
StartDate = CDate("01/01/" & Range("C3"))
EndDate = CDate("31/12/" & Range("C3"))
r = 7
For x = StartDate To EndDate
If Day(x) = 13 And Weekday(x, vbMonday) = 5 Then
Cells(r, 3) = Month(x)
r = r + 1
End If
Next
End Sub
Calculate next year with 3 Friday 13th. Good for 100 years different from year entered in cell C3
Sub ThreeFriday13()
Dim StartDate As Date
Dim EndDate As Date
Dim x As Long
Dim WhatYear As Integer
Dim Counter As Integer
Range("E7").ClearContents
StartDate = CDate("01/01/" & Range("C3") + 1)
EndDate = CDate("31/12/" & Range("C3") + 100)
Counter = 0
For x = StartDate To EndDate
If WhatYear Year(x) Then
WhatYear = Year(x)
'Different year so reset counter
Counter = 0
End If
If Day(x) = 13 And Weekday(x, vbMonday) = 5 Then
Counter = Counter + 1
If Counter = 3 Then
WhatYear = Year(x)
Exit For
End If
End If
Next
Range("E7") = WhatYear
End Sub
*RE-POST as not equal did not show earliuer
Calculate next year with 3 Friday 13th. Good for 100 years different from year entered in cell C3
Sub ThreeFriday13()
Dim StartDate As Date
Dim EndDate As Date
Dim x As Long
Dim WhatYear As Integer
Dim Counter As Integer
Range("E7").ClearContents
StartDate = CDate("01/01/" & Range("C3") + 1)
EndDate = CDate("31/12/" & Range("C3") + 100)
Counter = 0
For x = StartDate To EndDate
If WhatYear NE Year(x) Then
WhatYear = Year(x)
'Different year so reset counter
Counter = 0
End If
If Day(x) = 13 And Weekday(x, vbMonday) = 5 Then
Counter = Counter + 1
If Counter = 3 Then
WhatYear = Year(x)
Exit For
End If
End If
Next
Range("E7") = WhatYear
End Sub
earlier*
I've a doubt with using array formula here.
In sample workbook, I tried to replicate the formula again.
=IFERROR(SMALL(IF(WEEKDAY(DATE($C$3,ROW($A$1:$A$12),13))=6,ROW($A$1:$A$12)),$B7),"")
For this I selected C7 to C12, and typed the same formula and pressed ctrl+alt+Enter. But in all cells it is taking $B7 (and not $B7, $B8, $B9.... etc)
and since it is array formula I can't edit individual cell.
Please guide.
Thanks
Hi Chandoo,
Cool stuff. You need to clarify that the answer of 5 represents the 1st month in the year that has a Friday the 13th, and not the number of Fridays the 13th in the year. Subtle, but important difference.
Thanks,
Pablo
I like the MMULT() function far more, but here's how I would have tackled it. It uses an EDATE() base and MODE() over 100 years. I'm assuming that 100 years is enough time to catch the next year with 3 friday 13th's. Array entered, of course.
{=MODE(IFERROR(YEAR(IF((WEEKDAY(EDATE(DATE(C3, 1, 13), ROW(INDIRECT("1:1200"))))=6), EDATE(DATE(C3, 1, 13), ROW(INDIRECT("1:1200"))), "")), ""))}
Finding all the Friday the 13ths in a Year:
=SUMPRODUCT((DAY(ROW(INDIRECT(DATE(C3,1,1)&":"&DATE(C3,12,31))))=13)*(TEXT(ROW(INDIRECT(DATE(C3,1,1)&":"&DATE(C3,12,31))),"ddd")="Fri"))
{=sum(if(day.of.week(DATe($YEAR;{1;2;3;4;5;6;7;8;9;10;11;12};13);1)=6;1;0))}
just list the years