Sorting text is such a day to day activity that it always surprises me why Excel hasn’t provided a simple spreadsheet formula for doing it. Of course you can use the sorting menu command (menu > data > sort) but this requires manual steps (or VBA). Most of the times we get raw textual data from various sources and we need it to be sorted. While fooling with the COUNTIF() formula, I have realized a powerful yet little known feature that can be exploited to sort text using formulas.
We all know that countif() can be used to find the number of cells in a given range matching a criteria. But do you know that you can use COUNTIF() to find the number of cells in a range greater than or less than a particular value?
Well, that is the trick to sorting text. How?
For eg. assume range A1:A10 has c,b,d,f,h,j,e,a,i,g in them. When you write =countif(a1:a10,"<c") you will get 2 as the result.There are 2 cells with value less than “c”. In other words, the sort order of “c” in the given cells is 3 (since it has 2 cells less than “c”)
You can use this on your own list to fetch the alphabetical sort order of each text value like this:
Essentially the sort order formula looks like this: =countif(SORT RANGE, "<="&CURRENT CELL)
Once you have the sort order, arranging the cells in that order is a piece of cake. We just use VLOOKUP to do our job, like this: =VLOOKUP(1,SORT ORDER TABLE,2,FALSE). (PS: if you are worried about unique cells, which you should, then use this formula instead, =VLOOKUP(small(SORT ORDER COLUMN,1),SORT ORDER TABLE,2,FALSE)
What the heck is above formula doing? It is running a vlookup on the table containing original cells and their sort order to fetch the cell with sort order 1 (or the smallest sort order). Replace the 1 with 2 to get the next cell in the alphabetical order.
Download the workbook with alphabetical text sorting using formulas and see this in action.
Bonus tip: Instead of rewriting the vlookup formula with 2, 3, 4 as lookup value you can use excel's row() function to generate those running numbers for you. You just need to subtract correct value from the row().
Also read: Shuffling a list of cells in random order using formulas, More analytics / text processing tweaks
22 Responses to “Formula Forensic No 019. Converting uneven Text Strings to Time”
Why not let the TIME function take care of the math:
=TIME(LEFT(TEXT(A1,"000000"),2),MID(TEXT(A1,"000000"),3,2),RIGHT(TEXT(A1,"000000"),2))
I was going to point out the same thing, except to note that useing the time function and doing the divide method are not interchangeable.
I have spent hours investigating a spreadsheet working with a couple of years worth of hourly data, and found that the reason things weren't working is because the rounding on the divide method is only close to the correct time values. In order to have it work for comparisons, (like sub-totaling by time value, or pivoting) you MUST use the TIME function.
Great use of the TEXT function, Hui. I will be using this concept for sure.
Why not just.
=TEXT(A1,"00\:00\:00")*1
Regards
Elegant!
Hi Elias,
I tried to use your formula. But, it doesn't seem to work for me. I am getting an error message "The formula you typed contains an error". It seems I have the problem in using \: in the format. How can I overcome this?
Thanks
Manick, it isn't the /: that causes the problem. If you copy/paste it, you're getting “'s instead of the actual quotation marks that Excel uses. Change the quotation marks by deleting from the pasted formula and retype them.
Hi Manick...
use this alternate formula :
=1*TEXT(A1,"00"":""00"":""00")
note twice double quote each side of :
@Manick,
Did you copy the formula and pasted in Excel or did you typed? Also, do you use , or ; as separator of arguments?
Regards
@Elias: I had no problem using your formula, in fact, I have used your method to convert a number such as 20120419 to an Excel date using =TEXT(A1,"0000\/00\/00")*1. Thanks for posting.
@Joe: For date convertion you can use this as well.
=TEXT(A1,"00-00-00")*1
Regards
Sweet! It appears this also works with =TEXT(A1,"0-00-00")*1. I come from the old days when you counted every byte. I also like to try an make formulas as small as possible for the fun of it 🙂
Elias's suggestion is the simplest, but here is yet another way with TIME and MOD functions...
=TIME(MOD(A2/10000,100),MOD(A2/100,100),MOD(A2,100))
Since the seconds appear to always be 0, why not simply the input to minutes and above and save yourself the trouble of typing those zeroes...
0 => 0:00
1 => 1:00
10 => 10:00
100 => 1:00:00
etc.
Then just use this formula...
=TEXT(A1,"0\:00\:")*1
@ Rick, the numbers to convert are no typed, they are imported. Then your formula will return the wrong result.
Regards.
Hmm! My formula lost some backslash-zero combinations (two of them to be exact). The formula was supposed to be this...
=TEXT(A1,"0\:00\:\zero\zero")*1
where the words "zero" should actually be the number 0. Another way to write the formula is this...
=TEXT(A1,"0\:00\:""00""")*1
Hi Master,
While writing the formulae you have considered only upto "seconds factor" . I think you should take the centi-seconds factor also to achieve best results. Please look into it and rectify the problem...?
For Example.
In horse racing timings are noted in minute, seconds and centi-seconds, like if a horse finished in 70 seconds over a scurry of 1200 metres, is noted as 1.10 min. Nowadays it is noted in centi-seconds everywhere, like 70.00 if you want to convert it to centi seconds (should multiply by 100) = 7000 centi seconds. If you put this figure into your formula as a general number (7000) it will return as 1:10:00. As per your formula, it should be taken as 1 hour 10 seconds 0 minutes. However for a racing enthusiast like me it can be taken as 1 minute 10 seconds also.
Just look what happens if we race goers use this figure as 7000 centi seconds in your formulae, it will correctly show as 1 minute 10 seconds(?) Suppose a horse finishing over a 1200m in 70.60 seconds or in racing terms written as 1.10.60 mins, where 1 minute 10 seconds, & 60 centi-seconds can be counted as 7060, if you put this figure in the formula it will return as 1 minute 11 seconds, that is correct.
My point is if you can incorporate Centi Seconds in the formulae, it would be of great help to us also.
Thanks and regards.
Rajagopal (Mumbai)
Awesome techniques !
I tried with 235960 just to see if it will fail but this is great.
Although a little longer, this too work:
=CHOOSE(LEN(A2);A2/(24*3600);A2/(24*3600);LEFT(A2;1)/(24*60) + RIGHT(A2;2)/(24*3600);LEFT(A2;2)/(24*60) + RIGHT(A2;2)/(24*3600);LEFT(A2;1)/24 + MID(A2;2;2)/(24*60) + RIGHT(A2;2)/(24*3600);LEFT(A2;2)/24 + MID(A2;3;2)/(24*60) + RIGHT(A2;2)/(24*3600))
Converting uneven Text Strings to Time I have imported some data that comes in as a number that I need to convert to h:mm.
Just come across this while googling
find interesting challenge and come up with this
=TEXT(TEXT(SUBSTITUTE(A1,RIGHT(A1,1),""),"000000"),"00\:00\:00")
I need to convert a string of numbers representing average minutes, to reflect correct time values. For example, the numbers below currently represent 5.79 minutes, 15.82 minutes, etc.
I need to convert these values to their correct corresponding value within time parameters. So 5.79 would be something close to 5 minutes and 45 seconds.
5.79
15.82
3.92
12.40
6.70
3.62
I know there has to be a way to compute this in Excel, it can do anything, I believe!
Thank you for any and all assistance~
@Renee... You can use a formula like this. Assuming A1 has the minutes.seconds,
=INT(A1) + MOD(A1, 1)*0.6
If you want to see it in 5 minutes 45 seconds format, use
=INT(A1) & " mins " & ROUND(MOD(A1, 1)*0.6,2) & " secs"