One Control Three Cells

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A few weeks back I was asked “Is it possible to setup a control and then drag it down a range, so that it links to all the cells below it?

The answer is, of course, No.

But it got me thinking about why not allow one control to control a number of cells.

This post describes the solution, One Control Three Cells.

But it could just as easily be applied to a larger group of controls in a much larger system.

I have attached a sample file demonstrating the technique: Download sample file

The Old

In the sample file select the Old worksheet.

Typically if you had 3 cells and wanted to add automation, you would add a control to each cell.

 

Here I have added 3 controls. Each Control in Column E controls the Cells value to the left of it.

 

Each Control is independent and has no relationship to other cells or other controls.

Each control is setup and linked as shown below to a single cell.

This whole setup has to be applied individually to each control and associated cell.

The Cell link: dialog above cannot have a range

Well it can hold a range, but it only links the control to the upper left cell of the range, C3 in the example above.

But this got me thinking, why not link the control’s Cell Link to a Named Formula, which would return the range based on say where the active cell was.

 

The New

Change to the New Worksheet.

Notice how we now have a single control next to the 3 cells we wish to control.

You can see that in action here

 

Lets first examine what has been setup, then we will work through how it works.

First, Goto the Name Manager in the Formulas, Name Manager tab.

There are 3 Named Formula setup

SelectedRow : is a direct Link to cell A1

ControlRange: is a direct Link to cells C3:C5

ControlLink : is a named Formula containing a formula =OFFSET(New!$C$1,SelectedRow-1,0)

Next Right click on the Control and notice that it is linked to the ControlLink Named Formula.

There is more, but lets follow this through first.

Cell A1SelectedRow” contains the value 4.

The Named Formula ControlLink has a formula =OFFSET(New!$C$1, SelectedRow-1, 0)

which evaluates to =OFFSET(New!$C$1, 4-1, 0)

which simplifies to =OFFSET(New!$C$1, 3, 0)

The offset of C1 by 3 rows and 0 columns is C4

so the Named Formula ControlLink =OFFSET(New!$C$1, SelectedRow-1, 0)

returns the address of C4

So the Control uses an Address of C4 when the value of A1 is 4

But we didn’t change cell A1 ?

I did say there was more, and the more is a small piece of VBA code, which does some checking for us and places an appropriate value in A1

Goto VBA by pressing Alt+F11

Double click on the Sheet1(New) object and you should now see the code in the Code Pane

 

This tiny piece of code is the secret behind what makes this technique work.

Lets look at what it does

Private Sub Worksheet_SelectionChange(ByVal Target As Range)
  If Intersect(Target, Range(“ControlRange”)) Is Nothing Then
    Range(“SelectedRow”).Value = 0
    Exit Sub
  End If
Range(“SelectedRow”).Value = Target.Row
Application.CalculateFull
End Sub

The code is encapsulated in what is known as a Worksheet event.

Worksheet events, as the name implies, are events that occur on the worksheet.

In this case it is the SelectionChange event. That is every time you change the cell by clicking on it or using the keyboard arrows etc to change the active cell, this event is triggered and the enclosed code executed.

When the event is triggered the code starts and a variable Target is assigned to the new active cell. It is the Target of the events occurrence, ie: Your click on another cell.

The next piece of code handles what happens next

If Intersect(Target, Range(“ControlRange”)) Is Nothing Then
    Range(“SelectedRow”).Value = 0
    Exit Sub
End If

It basically says If the Target and the ControlRange Don’t Intersect then do the enclosed code

That is if the Target doesn’t intersect with the ControlRange, then set the SelectedRange cell A1 to 0

Then exit the subroutine

This is done so that cells that are selected whilst using the worksheet don’t interfere with the control.

But the important thing is what happens if the Target and ControlRange do intersect

The code says If there is not an intersection do what is inside the If / End If statements

If Intersect(Target, Range(“ControlRange”)) Is Nothing Then
    Range(“SelectedRow”).Value = 0
    Exit Sub
End If

But if the two ranges Do Intersect, the code simply passes over the included code and continues past to the next code.

The next code is

Range(“SelectedRow”).Value = Target.Row
Application.CalculateFull

This is where the SelectedRow cell A1 is assigned the value which is the Row number of the Target cell.

That is if we click in a cell in the ControlRange, the SelectedRow is assigned the value of the Target cells Row.

The worksheet is then calculated. This simply forces the named Formula to update.

Then the VBA finishes executing.

When the Worksheet was recalculated just above, the LinkedCell was updated.

Now when a user presses the Spin Button Control, it will use the new value in the LinkedCell named range as the Link cell and update the value of the cell according to whether you pressed the Up or Down arrow.

Final

This code can be applied to any number of controls as well as to complex ranges

If you wanted to control the values in the 9, dashed green, cells shown below highlighted

You would change the formula for ControlRange to

ControlRange =New!$B$8:$B$10,New!$C$11:$C$13,New!$B$14:$B$16

 

Comments:

What do you think about this technique?

Let me know in the comments below:

 

 

 

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40 Responses to “Looking up when the data won’t co-operate (case study)”

  1. Sumit Bansal says:

    Nice Trick.. Clever use of cell references

    Here is a formula I tried to create:
    =SUMPRODUCT(((NOT(ISERROR(SEARCH(L5,B4:H14))))*1),(B5:H15))

    It takes care of Caveat #1 (can handle text), but Caveat #2 remains.

  2. PeterB says:

    In situations like this, I will often use VBA to restructure the data (2 columns: dates and values) on to a new worksheet. I can then use this 'clean' source for data analysis (formula or pivot table).

    =SUMPRODUCT(((NOT(ISERROR(SEARCH(L5,B4:H14))))*1),(B5:H15)) and complex formulae in general are all very well but when you come back to them in a few weeks / months time, it is not at all easy to see what they do and what the limitations are.

  3. Somendra Misra says:

    Hi Chandoo,

    I had used this type of cell ref. various times while calculating average.
    But for the situation here try below formula . Note this is an array formula and must be confirmed with Ctrl+Shift+Enter.

    =SMALL(IF(MMULT((L5=B4:H14)*IF(ISNUMBER(B5:H15),B5:H15),{1;1;1;1;1;1;1}),MMULT((L5=B4:H14)*IF(ISNUMBER(B5:H15),B5:H15),{1;1;1;1;1;1;1})),1)

    Regards,

  4. Somendra Misra says:

    Hi, I think Using SEARCH in here will create a problem say there is a text like SUN and another text SUNLIGHT both result will be added by SUMPRODUCT.

    Regards,

  5. Elias says:

    Array option.

    =SUM(IF(MOD(ROW(B4:B14),2)=MOD(ROW(B4),2),IF(B4:H14=L5,B5:H15)))

    Regards

    • Michael (Micky) Avidan says:

      @Elias,
      Nice approach.
      Although not requested - the formula I suggested closes all possibilities.
      Criteria: _____ Value to retrieve:
      Date__________ Numeric
      Date__________Textual
      Textual________Numeric
      Textual________Textual
      While your formula copes with only the 3 first combinations.
      Michael (Micky) Avidan
      “Microsoft® Answer” – Wiki author & Forums Moderator
      “Microsoft®” MVP – Excel (2009-2015)
      ISRAEL

      • Elias says:

        @Michael,

        Sorry but I don’t understand your point. I believe the challenge was to return the summary of a given date. What is your really volatile formula doing that mine is not?

        Regards

        • Michael (Micky) Avidan says:

          @Elias,
          I didn't say that the challenge differs from what you just mentioned/aimed to nor that your formula doesn't provide the requested result.
          Please read my previous comment again and focus on the last combination (TEXT / TEXT).
          I, myself, always try to provide a global Formula that is capable to handle all sorts of data.
          Michael (Micky) Avidan
          “Microsoft® Answer” – Wiki author & Forums Moderator
          “Microsoft®” MVP – Excel (2009-2015)
          ISRAEL

          • Elias says:

            @Michael,
            I see your point, but you are missing the below points if you are trying to cover all sorts of data.

            What happened if the lookup value does not exist?

            Do you want the first, second, summary, concatenation of the values if the look value is repeated?

            See they are too many possibilities to be cover with just one formula.

            Regards

  6. Michael (Micky) Avidan says:

    1) The range: B4:H15 was named: RNG.
    2) The following Array Formula was "retrieved from my sleeve" and I hope it can be shorten.
    3) The formula seems to take care of BOTH(!) caveats.
    -------------------------------------------------------------------------------
    =OFFSET(INDIRECT(ADDRESS(SMALL(IF(RNG=L5,ROW(RNG),""),1),MOD(SMALL(IF(RNG=L5,(ROW(RNG))+COLUMN(RNG)/10),1),1)*10)),1,)
    -------------------------------------------------------------------------------
    Michael (Micky) Avidan
    “Microsoft® Answer” – Wiki author & Forums Moderator
    “Microsoft®” MVP – Excel (2009-2015)
    ISRAEL

    • Elias says:

      @Michael,

      Check what happened with your result if you type 41927 in D5.

      Regards

      • Michael (Micky) Avidan says:

        Correct. Didn't predict that.
        Will find time to work something out.
        Michael (Micky) Avidan
        “Microsoft® Answer” – Wiki author & Forums Moderator
        “Microsoft®” MVP – Excel (2009-2015)
        ISRAEL

      • Michael (Micky) Avidan says:

        @Elias,
        Let's hope the following Array Formula "closes all open doors".
        Again - it has nothing to do with your formula which works fine as long as the 3 first mentioned combinations are concerned.
        -------------------------------------------------------------------------------
        =INDEX(RNG,LARGE(IF(RNG=L5,MOD(ROW(RNG)-1,2)*(ROW(RNG)),""),1)-2,(MOD(SMALL(IF(RNG=L5,(ROW(RNG))+COLUMN(RNG)/10),1),1)*10)-1)
        -------------------------------------------------------------------------------
        Michael (Micky) Avidan
        “Microsoft® Answer” – Wiki author & Forums Moderator
        “Microsoft®” MVP – Excel (2009-2015)
        ISRAEL

        • Elias says:

          Ok, if you insist. The following will cover all the scenarios you listed. However, I’ll never recommend/use such of formula.

          Defined names:
          rDat = $B$4:$H$15
          rRow =ROW(rDat)-MIN(ROW(rDat))+1
          rCol =COLUMN(rDat)-MIN(COLUMN(rDat))+1
          rInc =MOD(rRow,2)=MOD(MIN(rRow),2)

          L6=INDEX(rDat,MAX(IF(rInc,IF(rDat=L5,rRow)))+1,MAX(IF(rInc,IF(rDat=L5,rCol))))
          Array Enter

          Regards

        • Frank says:

          @Michael,

          unfortunately, your array formula still seems to return wrong results (eg 3-Nov).

  7. Magda says:

    If data are organized like in the example, ie. looks like a calendar, the INDEX formula seems quite simple:
    =INDEX($B$4:$H$15,ROUNDDOWN((L5-B4)/7,0)*2+2,MOD((L5-B4),7)+1)

    • Marc says:

      Yours is effectively the same as what I just came up with, and I believe this is the optimal answer to this particular problem.

      My solution, before I saw yours:
      =OFFSET(B5,QUOTIENT(L5-B4,7)*2,MOD(L5-B4,7))

      OFFSET will work for an arbitrary list size, but INDEX might be easier to read.
      QUOTIENT does the round and division in a single step.

  8. XOR LX says:

    If there's an improvement over Elias's solution then I for one can't see it.

    Perhaps a non-CSE version which would also mean that only two references (B4:H14 and B5:H15), as opposed to three (B4, B4:B14 and and B5:H15), would require manually amending should the data range change, i.e.:

    =SUMPRODUCT((ISEVEN(ROW(B4:H14)-MIN(ROW(B4:H14)))*(B4:H14=L5)*B5:H15))

    I suppose we could make it a single, uniform range reference:

    =SUMPRODUCT((ISEVEN(ROW(B4:H14)-MIN(ROW(B4:H14)))*(B4:H14=L5)*OFFSET(B4:H14,1,,,)))

    which might be more appropriate should we e.g. wish to use a Defined Name for our range, i.e.:

    =SUMPRODUCT((ISEVEN(ROW(Rng)-MIN(ROW(Rng)))*(Rng=L5)*OFFSET(Rng,1,,,)))

    though whether that compensates for the extra, volatile function call is something to be debated.

    Regards

  9. Mahir says:

    I have tried something and then my Excel workbooks got shut down. Maybe that was too much?

    Anyway here is what I've tried:

    =SUMPRODUCT(INDEX(B5:H15;IF(ISEVEN(ROW(B5:H15));ROW(B5:B15)-ROW(B5)+1);{1\2\3\4\5\6\7}))

    Guess that was wrong? Would this approach work anyway?

    Looking forward to learn something from you Excel Experts.

  10. XOR LX says:

    @Michael Avidan

    As it stands that is not a very rigorous construction.

    You say "I, myself, always try to provide a global Formula that is capable to handle all sorts of data", which is a wonderful philosophy, but isn't it at least as important that we ensure that our formulas are independent of the row and column references of the data range in question, so that, should that range change, we do not have to re-work our solution?

    What happens with your formula, for example, if RNG is instead re-located one row down, from B4:H15 to B5:H16?

    When a formula is reliant upon the addition/subtraction of certain constants within the formula, which themselves are necessarily dependent upon the specific rows/columns in which the data lies at any given time (e.g. the -1 in MOD(ROW(RNG)-1,2)), then that formula is not a very flexible one.

    Hence the reason for my choice of a slightly longer construction:

    ROW(B4:H14)-MIN(ROW(B4:H14))

    which ensures that this part of the calculation is not dependent upon the precise location of the data range within the worksheet, and so will give correct answers even if that range is re-located.

    Regards

  11. Haz says:

    {=OFFSET(B4,MAX((B4:H15=L5)*ISODD(ROW(1:12))*ROW(1:12)),MAX((B4:H15=L5)*ISODD(ROW(1:12))*COLUMN(A:G))-1)}

    • Haz says:

      Non-array formula:
      =INDEX(B4:H15,SUMPRODUCT((B4:H15=L5)*(ROW(B4:H15)-ROW(B4)+1)*ISODD(ROW(B4:H15)-ROW(B4)+1))+1,SUMPRODUCT((B4:H15=L5)*(COLUMN(B4:H15)-COLUMN(B4)+1)*ISODD(ROW(B4:H15)-ROW(B4)+1)))

      Using one range (B4:H15), one reference (B4), one lookup value (L5) and no INDIRECT or OFFSET.

  12. MF says:

    My trial with defined names:

    DateRange
    =$B$4:$H$4,$B$6:$H$6,$B$8:$H$8,$B$10:$H$10,$B$12:$H$12,$B$14:$H$14

    Position
    =RANK('lookup problem'!$L$5,DateRange,1)

    L6
    =OFFSET(B4,ROUNDUP(Position/7,0)*2- 1,IF(MOD(Position,7)=0,6,MOD(Position,7)-1))

  13. Jeff Weir says:

    I'd probably just run with something like:
    =SUMPRODUCT((B4:H14=L5)*(MOD(ROW(B4:H14),2)=MOD(ROW(B4),2))*B5:H15)
    ...which is basically the same as Elias' but without the IFs

  14. Bermir says:

    The opposite of elegant but it works...

    =INDEX(B4:H15,IFERROR(MATCH(L5,B4:B14,0),0)+IFERROR(MATCH(L5,C4:C14,0),0)+IFERROR(MATCH(L5,D4:D14,0),0)+IFERROR(MATCH(L5,E4:E14,0),0)+IFERROR(MATCH(L5,F4:F14,0),0)+IFERROR(MATCH(L5,G4:G14,0),0)+IFERROR(MATCH(L5,H4:H14,0),0)+1,IFERROR(MATCH(L5,B4:H4,0),0)+IFERROR(MATCH(L5,B6:H6,0),0)+IFERROR(MATCH(L5,B8:H8,0),0)+IFERROR(MATCH(L5,B10:H10,0),0)+IFERROR(MATCH(L5,B12:H12,0),0)+IFERROR(MATCH(L5,B14:H14,0),0))

    • Bermir says:

      =INDEX(B4:H15,
      IFERROR(MATCH(L5,B4:B14,0),0)+
      IFERROR(MATCH(L5,C4:C14,0),0)+
      IFERROR(MATCH(L5,D4:D14,0),0)+
      IFERROR(MATCH(L5,E4:E14,0),0)+
      IFERROR(MATCH(L5,F4:F14,0),0)+
      IFERROR(MATCH(L5,G4:G14,0),0)+
      IFERROR(MATCH(L5,H4:H14,0),0)+1,
      IFERROR(MATCH(L5,B4:H4,0),0)+
      IFERROR(MATCH(L5,B6:H6,0),0)+
      IFERROR(MATCH(L5,B8:H8,0),0)+
      IFERROR(MATCH(L5,B10:H10,0),0)+
      IFERROR(MATCH(L5,B12:H12,0),0)+
      IFERROR(MATCH(L5,B14:H14,0),0))

  15. HF says:

    Named Range
    rownum = SUMPRODUCT(('lookup problem'!$B$4:$H$14='lookup problem'!$L$5)*ROW('lookup problem'!$B$4:$H$14)*ISEVEN(ROW('lookup problem'!$B$4:$H$14)))

    Formula
    =OFFSET($A$1,rownum,MATCH(L5,INDIRECT("$B"&rownum&":$H"&rownum),0))

  16. Venky says:

    How about SUM(IF(B4:H14=L5,B5:H15)) with array..it should work

  17. xen says:

    Sorry, Chandoo, you can't find stuff this way in every possible scenario.
    What if 2014-10-01 sales would equal 41.927 ? Which is serial number for 2014-10-15 ? SUMIF would fail to retrive correct answer. And your example data suggest that such number is possible in your table.

    It's better not to search through dates and numbers at the same time.

    If I'd solve a problem like this, it'd reformat table first so I get one column with dates and the other with numbers.

    In this case, formula to form date column would be:
    =INDIRECT(ADDRESS((INT((ROW()-4)/COUNT($B$4:$H$4))+1)*2+2;MOD(ROW()-4;COUNT($B$4:$H$4))+2;4;1))
    and numbers would be the same formula with sight adjustment (+3 instead of +2 at the end of first argument):
    =INDIRECT(ADDRESS((INT((ROW()-4)/COUNT($B$4:$H$4))+1)*2+3;MOD(ROW()-4;COUNT($B$4:$H$4))+2;4;1))

    And now you got two columns that you can safely use for searching!

  18. xen says:

    Oops, sorry, you actually mentioned that it doesn't work if number=date! I missed that part 🙁

  19. Vad says:

    ={OFFSET(A1,SUM((B4:H14=L5)*ROW((B4:H14))),SUM((B4:H14=L5)*COLUMN((B4:H14)))-1)}

    Works for all data... the solution I got for indirect looks little lengthy

  20. Rajesh says:

    I want to count last 20 records of a person, whose marks is greater than 2 and grade "manager". ....

    Assume A1 has got names (James, John...etc...)
    A2 "Manager"

    A3 "2"

    Someone please reply

  21. Rajesh says:

    I want to count last 20 records of a person, whose marks is greater than "2" and grade "Manager"

    Assume A1 "geroge" A2 "Michael" A3 "George" etc...name can found anywhere in the rows

    B1 "Manager" B2" clerk"

    C1 "2" C2, "4"

    please reply

  22. Marc says:

    Simplest I can come up with. No limitations for either 1 or 2. This does assume dates are an ordered list with 7 per row, and 2 rows per set. Assuming this is always true this will work for an arbitrary long list of dates.

    =OFFSET(B5,QUOTIENT($L$5-$B$4,7)*2,MOD($L$5-$B$4,7))

    • Michael (Micky) Avidan says:

      @Marc,
      Nice approach - however, as there are no "Negative Dates" - try:
      =OFFSET(B5,INT(L5-B4)/7)*2,MOD(L5-B4,7))
      ——————————————————————————-
      Michael (Micky) Avidan
      “Microsoft® Answer” – Wiki author & Forums Moderator
      “Microsoft®” MVP – Excel (2009-2015)
      ISRAEL

  23. Vijaykumar Shetye says:

    =OFFSET(B4,ROUNDUP((L5-41911+1)/7,0)*2-1,MOD(L5-41911,7))

    B4 has been used as reference cell for OFFSET().

    FOR ROWS:
    ROUNDUP(....,0) gives the integer value of a division. In case of presence of a remainder, ROUNDUP will add 1 to the Quotient.
    As opposed to ROUNDUP(), the INT() or QUOTIENT() functions eliminate the remainder.

    41911 = 01-Sept-2014, the first date in the data.

    *2 has been used because there are 2 columns per set of data.

    /7 has been used because there are 7 columns per set of data.

    For columns
    MOD(L5-41911,7))

    Vijaykumar Shetye,
    Panaji, Goa, India

  24. Awais says:

    This is how i did it

    {=INDEX(B4:H15, MAX((L5=B4:H15)*ROW(B4:H15))-2, MAX((L5=B4:H15)*COLUMN(B4:H15))-1 )}

  25. Paul says:

    Here's my solution:

    =INDEX(B4:H15,MATCH(1,MMULT(--(B4:H15=L5),TRANSPOSE(COLUMN(B4:H15)^0)),0)+1,MATCH(1,MMULT(TRANSPOSE(--(B4:H15=L5)),ROW(B4:H15)^0),0))

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