M Mohandas Member Mar 5, 2014 #1 Please help me in this format attached . Attachments Book1.xls 30.5 KB · Views: 9
Somendra Misra Excel Ninja Mar 5, 2014 #2 Hi, Is there any logic behind No. of eaches per case (column K)? or we can use the cell value directly. Regards,
Hi, Is there any logic behind No. of eaches per case (column K)? or we can use the cell value directly. Regards,
Faseeh Excel Ninja Mar 5, 2014 #6 @Mohandas : Please try in M3 Code: =LEFT(B3,FIND("/",B3)-1)+0+(MID(B3,FIND("/",B3)+1,4)+0)/K3
Somendra Misra Excel Ninja Mar 5, 2014 #7 Try in U3 amd copy down, =SUM(IF(P3=$A$3:$A$35,MID($B$3:$B$35,1,SEARCH("/",$B$3:$B$35)-1),0)+0,IFERROR(IF(P3=$A$3:$A$35,MID($B$3:$B$35,SEARCH("/",$B$3:$B$35)+1,256)+0,0)/IF(P3=$H$3:$H$35,$K$3:$K$35,1),0)) Regards,
Try in U3 amd copy down, =SUM(IF(P3=$A$3:$A$35,MID($B$3:$B$35,1,SEARCH("/",$B$3:$B$35)-1),0)+0,IFERROR(IF(P3=$A$3:$A$35,MID($B$3:$B$35,SEARCH("/",$B$3:$B$35)+1,256)+0,0)/IF(P3=$H$3:$H$35,$K$3:$K$35,1),0)) Regards,
M Mohandas Member Mar 5, 2014 #8 THis is working out but some time. Some codes are appeaching double time is there any way to do it
Somendra Misra Excel Ninja Mar 5, 2014 #9 Just check my code, it is dealing with duplicates. (for e.g. in you sample data 12199187 is twice.)