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Weighted average problem with negative numbers in data set

Maja

New Member
Hi,

Let's say I have 4 values A, B, C and D. Let's say they each contribute 30%, 30%, 20% and 20% towards some final value X.

So my weighted average formula is:

X = [0.3(A) + 0.3(B) + 0.2(C) + 0.2(D)] / [0.3+0.3+0.2+0.2]

But what if the situation is such that values C and D contribute negatively to the over all value X?

As a sports analogy using a hypothetical situation, let's say I am calculating a Football Quarterback's rating using my own method as follows:

A = Yards per Attempt (I want this to be high, so this is a positive value) - 30% weight
B = Number of Touchdowns (I want this to be high, so this is a positive value) - 30% weight
C = Number of Incomplete passes (I want this number to be low/miniumum and it contributes negatively to the overall rating) - 20% weight
D = Number of Interceptions (Needs to be minimized and contributes negatively to the overall rating) - 20% weight

So for my overall weighted average QB rating can I use this formula?

X = [0.3(A) + 0.3(B) - 0.2(C) - 0.2(D)] / [0.3+0.3+0.2+0.2]

Also does it matter if the values of A, B, C and D have greatly different values? Take some hypothetical numbers in my example:

A = Yards per Attempt = 7
B = Number of TDs = 3
C = Number of incompletions = 15
D = Number of Interceptions = 1

As you can see the numbers vary by quite a bit. With my formula X = [0.3(A) + 0.3(B) - 0.2(C) - 0.2(D)] am I unintentionally giving extra weight to certain values just because they numbers themselves are much larger than the others?

What would be the best way to go about solving such a problem where some values contribute and other take away from the final value, each number having its own contribution in the whole scheme of things?

Thanks,
Maja
 

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I don't see any issues with the negative weighting.

Using factors that are significantly different than each other will certainly cause you some issues. Your best way around that is to set the factors up as a percentage. For example, Number of Incompletions and Number of Interceptions could be Percent Incomplete (Incomplete/Total Passes) and Percent Intercepted (Interceptions/Total Passes). For Yards per Attempt, you could view them as percent of field (yards/100). For Number of TDs, set an arbitrary maximum (ex 10) and divide everything by that. In this way, all of your factors are now equal.
 
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