Decimal not showing if if third value is zero

[aparvez007]

Hi All,

Need help to correct code convert number to word.
e.g. if value is 1202.121 its showing correct but if 1202.120 then last zero not showing in decimal place.

Option Explicit
'Main Function
Function SpellNumber(ByVal mynumber)
Dim Pounds, Pence, Temp
Dim DecimalPlace, Count
ReDim Place(9) As String
Place(2) = " Thousand "
Place(3) = " Million "
Place(4) = " Billion "
Place(5) = " Trillion "
' String representation of amount.
mynumber = Trim(Str(mynumber))
' Position of decimal place 0 if none.
DecimalPlace = InStr(mynumber, ".")
' Convert Pence and set MyNumber to pound amount.
If DecimalPlace > 0 Then
'Pence = GetTens(Left(Mid(MyNumber, DecimalPlace + 1) & _
'"00", 2))
Pence = Right(mynumber, Len(mynumber) - DecimalPlace)
If Pence < 10 And Len(Pence) = 1 Then Pence = Pence * 1000
mynumber = Trim(Left(mynumber, DecimalPlace - 1))
End If
Count = 1
Do While mynumber <> ""
Temp = GetHundreds(Right(mynumber, 3))
If Temp <> "" Then Pounds = Temp & Place(Count) & Pounds
If Len(mynumber) > 3 Then
mynumber = Left(mynumber, Len(mynumber) - 3)
Else
mynumber = ""
End If
Count = Count + 1
Loop
Select Case Pounds
Case ""
Pounds = ""
Case "One"
Pounds = ""
Case Else
Pounds = Pounds & ""
End Select
Select Case Pence
Case ""
Pence = "000"
Case "One"
Pence = " "
Case Else
Pence = " " & Pence & ""
End Select
'SpellNumber = Pounds & Pence
SpellNumber = Pounds & " and " & Pence & "/1000 Only"
End Function

' Converts a number from 100-999 into text
Function GetHundreds(ByVal mynumber)
Dim Result As String
If Val(mynumber) = 0 Then Exit Function
mynumber = Right("000" & mynumber, 3)
' Convert the hundreds place.
If Mid(mynumber, 1, 1) <> "0" Then
Result = GetDigit(Mid(mynumber, 1, 1)) & " Hundred "
End If
' Convert the tens and ones place.
If Mid(mynumber, 2, 1) <> "0" Then
Result = Result & GetTens(Mid(mynumber, 2))
Else
Result = Result & GetDigit(Mid(mynumber, 3))
End If
GetHundreds = Result
End Function

' Converts a number from 10 to 99 into text.
Function GetTens(TensText)
Dim Result As String
Result = "" ' Null out the temporary function value.
If Val(Left(TensText, 1)) = 1 Then ' If value between 10-19...
Select Case Val(TensText)
Case 10: Result = "Ten"
Case 11: Result = "Eleven"
Case 12: Result = "Twelve"
Case 13: Result = "Thirteen"
Case 14: Result = "Fourteen"
Case 15: Result = "Fifteen"
Case 16: Result = "Sixteen"
Case 17: Result = "Seventeen"
Case 18: Result = "Eighteen"
Case 19: Result = "Nineteen"
Case Else
End Select
Else ' If value between 20-99...
Select Case Val(Left(TensText, 1))
Case 2: Result = "Twenty "
Case 3: Result = "Thirty "
Case 4: Result = "Forty "
Case 5: Result = "Fifty "
Case 6: Result = "Sixty "
Case 7: Result = "Seventy "
Case 8: Result = "Eighty "
Case 9: Result = "Ninety "
Case Else
End Select
Result = Result & GetDigit _
(Right(TensText, 1)) ' Retrieve ones place.
End If
GetTens = Result
End Function

' Converts a number from 1 to 9 into text.
Function GetDigit(Digit)
Select Case Val(Digit)
Case 1: GetDigit = "One"
Case 2: GetDigit = "Two"
Case 3: GetDigit = "Three"
Case 4: GetDigit = "Four"
Case 5: GetDigit = "Five"
Case 6: GetDigit = "Six"
Case 7: GetDigit = "Seven"
Case 8: GetDigit = "Eight"
Case 9: GetDigit = "Nine"
Case Else: GetDigit = ""
End Select
End Function

 

[Luke M]

Line 12 needs to be changed. Should be

myNumber = Trim(myNumber.Text)

The .Text property will return a String showing what the Cell is showing (not cell value), which preserves the trailing 0 and removes the need for Str method.