Bosco, good afternoon, could you please explain to me that you use this part of the chain, and specifically "A1 & 1/17", and not for example "A1 & 1/5", or "A1 & 1/100", or any other number.FIND ({1,2,3,4,5,6,7,8,9,0}, A1 & 1/17)
Hi ,Bosco, good afternoon, could you please explain to me that you use this part of the chain, and specifically "A1 & 1/17", and not for example "A1 & 1/5", or "A1 & 1/100", or any other number.
Thanks for your attention
Greetings Jorge
In additional to Narayan's explanationBosco, good afternoon, could you please explain to me that you use this part of the chain, and specifically "A1 & 1/17", and not for example "A1 & 1/5", or "A1 & 1/100", or any other number.
Thanks for your attention
Greetings Jorge
Formula I've posted will work as it is based on delimiter:Team,
I was using thr formula =0+MID(A1,MIN(FIND({1,2,3,4,5,6,7,8,9,0},A1&1/17)),4)
and it was working fine to extra 4 digit numbers from text like FTT_CIA_6895_Tom_Harry
Need 1 more help, there are some new ids which has only 3 digits numbers like FTT_CIA_895_Tom_Harry